If b = 9 then the value of 10b is 90
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
10b
72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
9
If b = 9 then the value of 10b is 90
2(7b + 9)(b - 2)
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
10b
The given expression can be simplified to: 3b-a
If it's a one-digit number then any 1-digit number will do (0...9) 2-digits numbers : ab=10a+b=a+b it's not possible unless a=0 For 3-digits: abc=100a+10b+c=a+b+c => 100a+10b = a+b it' not possible unless a=b=0 And so on...
It is equivalent to: 10b-25
The primary equation is N = 100a + 10b + c for integers a, b and c. Also, 100a + 10b + c = 11m where m = a^2 + b^2 + c^2. Substitution and simplification yield 100a + 10b + c = 11a^2 + 11b^2 + 11c^2. There are two cases, where b = a + c, or b = a + c - 11. Solving these two cases results in the answer of N = 550, 803.
-5 + 10b = -3110b = -26b = -2.6
72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
The equation 10b = 11 can be solved for b by dividing both sides of the equation by 10. b = 11/10 or 1.1
10b