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What value 10b when b 9?
If b = 9 then the value of 10b is 90
Find the digits of a two digit number whose sum is 7 and the number increases by nine when the digits are transposed?
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
What is b plus 9b?
10b
If a number consists of two digits which add up to nine and when the digits are reversed the original number is decreased by forty five then what was the original number?
72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
What is 10a x 10b equal to?
9
What value 10b when b 9?
If b = 9 then the value of 10b is 90
How do you solve this equation 14b2-10b-36?
2(7b + 9)(b - 2)
Find the digits of a two digit number whose sum is 7 and the number increases by nine when the digits are transposed?
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
What is b plus 9b?
10b
What is 3a plus 2b-4a plus b?
The given expression can be simplified to: 3b-a
How can I determine all 3 digit numbers which are equal to 11 times the sum of the squares of their digits?
The primary equation is N = 100a + 10b + c for integers a, b and c. Also, 100a + 10b + c = 11m where m = a^2 + b^2 + c^2. Substitution and simplification yield 100a + 10b + c = 11a^2 + 11b^2 + 11c^2. There are two cases, where b = a + c, or b = a + c - 11. Solving these two cases results in the answer of N = 550, 803.
What is the value of b if -5 plus 10b equals -31?
-5 + 10b = -3110b = -26b = -2.6
If a number consists of two digits which add up to nine and when the digits are reversed the original number is decreased by forty five then what was the original number?
72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
What is the gcf of 30 ab and 50 b?
10b
What is 10a x 10b equal to?
9
What does 34a plus 10b equal?
That depends what the value of a and b are.
Why does the 1089 maths trick work?
let a, b, c denote the three digits of the original number, then the three-digit number is 100a+10b+c. The reverse is 100c+10b+a. Subtract: (100a+10b+c)-(100c+10b+a) to get 99(a-c). Since the digits were decreasing, (a-c) is at least 2 and no greater than 9, so the result must be one of 198, 297, 396, 495, 594, 693, 792, or 891. When you add any one of those numbers to the reverse of itself, you get 1089
