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10(b - 3) plus 5?
It is equivalent to: 10b-25
What is the smallest possible difference between two different nine digit integers each of which includes all of the digits 1 to 9?
Pick a and b as the last two digits (and we may assume a is greater than b). Make the remaining first seven digits the same as each other (any way will be fine). The last two digits will be ab for the first number and ba for the second number. The value of ab is 10a+b, the value of ba is 10b+a. The difference is (10a+b)-(10b+a)= 9a-9b = 9(a-b). To minimise this we just make a and b consecutive integers - there are eight ways of doing this. There are 7! ways of arranging the first seven digits. So 8! ways of choosing the numbers.
How do you slove 10b equals 11?
The equation 10b = 11 can be solved for b by dividing both sides of the equation by 10. b = 11/10 or 1.1
A number written as the sum of the values of it's digits?
If it's a one-digit number then any 1-digit number will do (0...9) 2-digits numbers : ab=10a+b=a+b it's not possible unless a=0 For 3-digits: abc=100a+10b+c=a+b+c => 100a+10b = a+b it' not possible unless a=b=0 And so on...
What is -b plus 3 from -11b-4?
It is -10b - 7.
What value 10b when b 9?
If b = 9 then the value of 10b is 90
10b - 9 if b 2?
11
What is the value of b if -5 plus 10b equals -31?
-5 + 10b = -3110b = -26b = -2.6
Find the digits of a two digit number whose sum is 7 and the number increases by nine when the digits are transposed?
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
What does 34a plus 10b equal?
That depends what the value of a and b are.
What is b plus 9b?
10b
How do you solve this equation 14b2-10b-36?
2(7b + 9)(b - 2)
What is 3a plus 2b-4a plus b?
The given expression can be simplified to: 3b-a
10(b - 3) plus 5?
It is equivalent to: 10b-25
What is the smallest possible difference between two different nine digit integers each of which includes all of the digits 1 to 9?
Pick a and b as the last two digits (and we may assume a is greater than b). Make the remaining first seven digits the same as each other (any way will be fine). The last two digits will be ab for the first number and ba for the second number. The value of ab is 10a+b, the value of ba is 10b+a. The difference is (10a+b)-(10b+a)= 9a-9b = 9(a-b). To minimise this we just make a and b consecutive integers - there are eight ways of doing this. There are 7! ways of arranging the first seven digits. So 8! ways of choosing the numbers.
How do you slove 10b equals 11?
The equation 10b = 11 can be solved for b by dividing both sides of the equation by 10. b = 11/10 or 1.1
What is the gcf of 30 ab and 50 b?
10b
