0
What else can I help you with?
10(b - 3) plus 5?
It is equivalent to: 10b-25
When Clara totaled her scores she inadvertently reversed the units digit and the tens digit of one score. By which of the following might her incorrect sum have differed from the correct one?
When Clara reversed the units digit and tens digit of one score, the difference between the incorrect and correct sum would be determined by the value of the digits switched. If the original score was (10a + b) (where (a) is the tens digit and (b) is the units digit), the incorrect score would be (10b + a). The difference between these two scores is ( (10b + a) - (10a + b) = 9(b - a) ). Therefore, her incorrect sum might have differed from the correct one by a multiple of 9, specifically (9(b - a)), which could be any integer value that is a multiple of 9.
How do you slove 10b equals 11?
The equation 10b = 11 can be solved for b by dividing both sides of the equation by 10. b = 11/10 or 1.1
A number written as the sum of the values of it's digits?
If it's a one-digit number then any 1-digit number will do (0...9) 2-digits numbers : ab=10a+b=a+b it's not possible unless a=0 For 3-digits: abc=100a+10b+c=a+b+c => 100a+10b = a+b it' not possible unless a=b=0 And so on...
What is -b plus 3 from -11b-4?
It is -10b - 7.
What value 10b when b 9?
If b = 9 then the value of 10b is 90
10b - 9 if b 2?
11
What is the value of b if -5 plus 10b equals -31?
-5 + 10b = -3110b = -26b = -2.6
Find the digits of a two digit number whose sum is 7 and the number increases by nine when the digits are transposed?
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
What does 34a plus 10b equal?
That depends what the value of a and b are.
What is b plus 9b?
10b
How do you solve this equation 14b2-10b-36?
2(7b + 9)(b - 2)
What is 3a plus 2b-4a plus b?
The given expression can be simplified to: 3b-a
10(b - 3) plus 5?
It is equivalent to: 10b-25
When Clara totaled her scores she inadvertently reversed the units digit and the tens digit of one score. By which of the following might her incorrect sum have differed from the correct one?
When Clara reversed the units digit and tens digit of one score, the difference between the incorrect and correct sum would be determined by the value of the digits switched. If the original score was (10a + b) (where (a) is the tens digit and (b) is the units digit), the incorrect score would be (10b + a). The difference between these two scores is ( (10b + a) - (10a + b) = 9(b - a) ). Therefore, her incorrect sum might have differed from the correct one by a multiple of 9, specifically (9(b - a)), which could be any integer value that is a multiple of 9.
How do you slove 10b equals 11?
The equation 10b = 11 can be solved for b by dividing both sides of the equation by 10. b = 11/10 or 1.1
What is the gcf of 30 ab and 50 b?
10b
