72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
11yrs.
192
To total 17 the two digits must be 8 and 9! The original number was 98.
Find a four digit number whose digits will be reversed when multiplied by nine?
Let the 2 digit number be 10a +b. Then: a + b = 15 10a + b - 27 = 10b + a => 9a -9b = 27 => a - b = 3 adding the first and last equations gives: 2a = 18 => a = 9 and substituting in the first gives: 9 + b = 15 => b = 6 meaning the original number is 96.
after 11yrs.
11yrs.
The number is 36
192
9631. The sequence consists of the prime numbers which, when their digits are reversed, are perfect squares.
17
To total 17 the two digits must be 8 and 9! The original number was 98.
An eight digit number with one zero cannot remain the same when its digits are reversed. It must have an even number of 0s.
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
27
Find a four digit number whose digits will be reversed when multiplied by nine?
five digits number when you multiply by four is the same the number when you reversed it is 21978*4 = 87912