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If a number consists of two digits which add up to nine and when the digits are reversed the original number is decreased by forty five then what was the original number?
Wiki User
∙ 15y ago
72 1) a+b=9 2) ab-ba=45==> 10a+b-(10b-a)=45==>9a-9b=45==>a-b=5 per (1) and (2) a+b+a-b=9+5 ==> 2a=14==>a=7 per (2) a-b=5==> b=2 ab=72; ba=27
Wiki User
∙ 15y ago
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