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If given the 10th term in the above geometric sequence which is 1536 what would you need to do to find the 11th term?
To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
Let k be the constant of proportionality and let q r s and t be positive real number variables. If q varies directly with the cube of r inversely with s and inversely with the square root of t which o?
q = k*r^3/(s*sqrt(t))
How much is 1 mm in a m?
Mo t h e r f o c k e r ! !
In r and k selection what does this r and k means?
get off the computer and do your work.
If k over 3 plus k over 4 equals 1 what is k?
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
