To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
q = k*r^3/(s*sqrt(t))
Mo t h e r f o c k e r ! !
get off the computer and do your work.
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
12 knigths of the round table
12 Knights of the Round Table
Knight Rider - 1982 K-I-T-T- vs- K-A-R-R- 3-6 was released on: USA: 4 November 1984 Netherlands: 14 August 1985 UK: 13 December 1985 Finland: 12 February 1986
proof of theorem r'(t) x r''(t) K(t) = r'(t)3 proof of theorem r'(t) x r''(t) K(t) = r'(t)3
k a r a t -or- c a r a t
R. T. K. has written: 'A visit to the spring on the hillside, or, The temperance question'
To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
K-R-I-T Motor Car Company was created in 1909.
I thinks that might be r k r j s k s j t k Repeats the sequence of the letter rr ss tt. . . . and k...j ... k ... j ... k ... j ... k ---> line 1 r......r.....s....s.....t.... ---> line 2 Match line 1 with line 2. I hope it is clear and correct.
A = P*(1+R/100)T Where A = amount P = Principal R = Interest Rate (in percentage), and T = Time Since R and T are known, you can calculate (1+R/100)T = k, say. Then A = P*k so that P = A/k
T. K. Carter was born on 1956-12-18.
T. K. Wetherell was born on 1945-12-22.