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What five numbers have a median of 12 a mode of 10 and mean of 12?
Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a ≤ b ≤ c ≤ d ≤ e, then:median = 12 → c = 12leaving only two numbers (a, b) ≤ 12.mode = 10 → two or more numbers equal 10 (which is less than 12) → a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 → d + e = 28 → d = 13, e = 15→ {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]
In what percent oxygen comprises the weight of earth's continental crust a 12 b 27 c 47 d 63 e 85?
12
If a equals b and b equals c and c equals d and and d equals e then what does e equal?
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
What are the answers for intermediate maths challenge 2012?
a d e e c b a e d d a c
12 equals N in a D?
12=n in a d
