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Holden Romaguera
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What are the zeros of f(x) = (x – 1)(x 6) Select all that apply: A. x = –6 B. x = 6 C. x = 1 D. x = –1?
x=-6, x=1
How many sixths are there in 23?
138 1 = 6 x 1/6 23 = 23 x 6 x 1/6 = 138 x 1/6
How do you write the product of 9 and the sum of 6 and x is 1 in a equation?
9(6 + x) = 1
9x minus 53 equals 6 divided by x?
9x-53=6/x 9x2-53x=6 9x2-53x-6=0 9x2+x-54x-6=0 x(9x+1)-6(9x+1)=0 (9x+1)x(x-6)=0 9x+1=0 or x-6=0 9x=-1 or x=6 x=-1/9 or x=6
What are the odds of rolling 4 of a kind with 5 dice?
It would be 1/6 with 1 dice. To get 5 out of FIVE it would be 1/6 X 1/6 x 1/6 X 1/6 X 1/6 = 1/7776 odds. 4/5 would be 1/216
What is the chances for having three sixes on a 3 dice?
The chances are (1/6) x (1/6) x (1/6)The chances are (1/6) x (1/6) x (1/6)The chances are (1/6) x (1/6) x (1/6)The chances are (1/6) x (1/6) x (1/6)
What are the zeros of f(x) = (x – 1)(x 6) Select all that apply: A. x = –6 B. x = 6 C. x = 1 D. x = –1?
x=-6, x=1
How many sixths are there in 23?
138 1 = 6 x 1/6 23 = 23 x 6 x 1/6 = 138 x 1/6
How do you write the product of 9 and the sum of 6 and x is 1 in a equation?
9(6 + x) = 1
9x minus 53 equals 6 divided by x?
9x-53=6/x 9x2-53x=6 9x2-53x-6=0 9x2+x-54x-6=0 x(9x+1)-6(9x+1)=0 (9x+1)x(x-6)=0 9x+1=0 or x-6=0 9x=-1 or x=6 x=-1/9 or x=6
What numbers multiply to get 6?
1, 2, 3, 6: 1 x 6, 2 x 3.
Odds of rolling 6 ones with 6 dice?
Probability of rolling a ' 1 ' with a single cube = 1 / 6Probability of rolling six 1s with 6 cubes =(1/6) x (1/6) x (1/6) x (1/6) x (1/6) x (1/6) = 1/46,656 = 0.000021433 (rounded) = 0.0021433%
Factor x2 equals -5x-6?
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
What is x2 plus 5x-6 in factoring?
x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)
Math factors of 6?
factors of 6 are: 1, 2, 3, and 6. 1 x 6=6, 2 x 3=6, 3 x 2=6, 6 x 1 = 6
Factor the following 5x2 x - 6?
5x2 + x - 6 = (5x + 6)(x - 1) 5x2 - x - 6 = (5x - 6)(x + 1)
How do you write x3 plus 2x2-5x-6 in factored form?
x3 + 2x2 - 5x - 6 = x3 + x2 + x2 + x - 6x - 6 = x2(x + 1) + x(x + 1) - 6(x + 1) = (x + 1)(x2 + x - 6) = (x + 1)(x2 + 3x - 2x - 6) = (x + 1)[x(x + 3) - 2(x + 3)] = (x + 1)(x + 3)(x - 2)
