32m
11x5 m is 32m
64 m2 perimeter_of_square = 4 x side_length ⇒ side_length = perimeter_of_square ÷ 4 area_of_square = side_length2 Thus if perimeter is 32 m: side_length = 32 m ÷ 4 = 8 m ⇒ area = (8 m)2 = 64 m2
to find a perimeter of a triangle you need the add the lengths of the sides. So in this case, the sides are 18 + 32 + 252 so the answer would be 302meters Just a little hint : keep in mind what the measurements are in (i.e. centimeters, meters...) . you might to convert for some problems.
It is: 32/4 = 8m in length
A rectangle measuring 3.2m x 10m has an area of 32m
A rectangle measuring 3.2m x 10m has an area of 32m.
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The area of a square that has a perimeter of 32m is: 64 m2
If: 8m = 32m+96 Then: m = -4
You mean 32m width and height? Cuz you need to know both to get the area. You just multiply them together. If your height is 32m and your width 32m then area would be 1024m, it's simple math.
Approx. 33.5 m To solve you use Pythagorean Theorem: c2 = a2 + b2 , where c is the hypotenuse of the right triangle. In this case c will be the length of the guy wire. The length of one leg of the triangle will 10m and the other will be 32m (40m - 8m) So, c2 = (10m)2 + (32m)2 c2 = 100m2 + 1024m2 = 1124m2 c = SQRT (1124m2) or c = 33.53 m
32m
32m
32m² = 344.45ft²
32m. Area_of_square = side2 -> side = √area -> side = √64m2 = 8m Perimeter_of_square = 4 x side -> Perimeter = 4 x 8m = 32m
11x5 m is 32m