K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
3k-1=k+2 2k=3 k=3/2=1.5
9 - 2k - 3 = k Add 2k to both sides: 9 - 3 = k + 2k Combine like terms: 6 = 3k Divide both sides by 3: 2 = k
(k*m)3 = k3*m3
For a parabola with a y=... directrix, it is of the form: (x - h)^2 = 4p(y - k) with vertex (h, k), focus (h, k + p) and directrix y = k - p With a focus of (3, 6) and a directrix of y = 4, this means: (h, k + p) = (3, 6) → k + p = 6 y = k - p = 4 → k = 5, p = 1 (solving the simultaneous equations) → vertex is (3, 5) → parabola is (x - 3)^2 = 4(y - 5) which can be rearranged into y = 1/4 x^2 - 3/2 x + 29/4
84-k41-89.3
Potassium-40 (K40) is the most abundant isotope of potassium, followed by potassium-39 (K39) and then potassium-41 (K41).
If: k+3=-3 Then: k=-3-3 k=-6
As an algebraic expression it is: k-3
It is because 3 is a factor of 9. So if 9 is a factor of some number X, then X = k*9 for the factor pair 9 and k But X = k*9 = k*(3*3) = (k*3)*3 so that X is k*3 times 3 ie it is a multiple of 3.
3 is an integer and not a fraction. However, it can be expressed in rational form as (3*k)/k where k is an integer.
3 - k
k^2 + k = k^2 + k k^2 x k = k^3
Slope = (change in y)/change in x so (3 - k)/(-6 - 0) = (3 - k)/-6 = 1 3 - k = -6 3 = k - 6 3 + 6 = k k = 9 so the points are (0,9) and (-6,3) The actual formula of the line could be written as y = x + 9
3*0 = 0 Dividing both sides by 3 gives 0 = 0/3 and therefore 0/3 is defined and is equal to 0. However, there is no number, k, such that k*0 = 3 and so division by 0 is not defined. If there were such a number k, then you could divide both sides by k to give 0 = 3/k. But there is no such k.
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
The values of k can be: 5 or -3