It is x - y + 2 = 0
((15xy2)/(x2+5x+6))/((5x2y)/(2x2+7x+3)) =(15xy2/5x2y)*(2x2+7x+3)/(x2+5x+6) =(3y/x)*(((2x+1)(x+3))/((x+2)(x+3) =(3y(2x+1))/(x(x+2)) =(6xy+3y)/(x2+2x)
9 plus 16=25 3 squared is the same as 3 times three and 4 squared is the same as 4 times 4 3 times 3 + 4 times 4 9 plus 16 = 25
"3 times" 3 * "the quantity" ( something ) "2 plus a" 2 + a. Now combine. "Three times the quantity 2 plus a" 3*(2+a) multiply 2 and a by 3. (distribute) 6 + 3a
x2 + 8x2 = 9x2
68.3
It is x - y + 2 = 0
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
This expression factors as x -1 quantity squared.
((15xy2)/(x2+5x+6))/((5x2y)/(2x2+7x+3)) =(15xy2/5x2y)*(2x2+7x+3)/(x2+5x+6) =(3y/x)*(((2x+1)(x+3))/((x+2)(x+3) =(3y(2x+1))/(x(x+2)) =(6xy+3y)/(x2+2x)
They are at x = -3 and x = -2.
9 plus 16=25 3 squared is the same as 3 times three and 4 squared is the same as 4 times 4 3 times 3 + 4 times 4 9 plus 16 = 25
3
(9 - y)(a + 5)
I'm pretty sure it's x sqaured plus seven
It is the straight line through the points (0, -1) and (1, 0).
"3 times" 3 * "the quantity" ( something ) "2 plus a" 2 + a. Now combine. "Three times the quantity 2 plus a" 3*(2+a) multiply 2 and a by 3. (distribute) 6 + 3a