The indefinite integral of (1/x^2)*dx is -1/x+C.
There can be no definite integral because the limits of integration are not specified. The indefinite integral of 1/x2 is -1/x + C
âˆ« f'(x)/(p2 + q2f(x)2) dx = [1/(pq)]arctan(qf(x)/p)
- ln ((x^2)-4)
âˆ« f'(x)/[f(x)âˆš(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.
âˆ« f'(x)/âˆš(a2 - f(x)2) dx = arcsin(f(x)/a) + C C is the constant of integration.
integral of radical sinx
âˆ« f'(x)/( q2f(x)2 - p2) dx = [1/(2pq)ln[(qf(x) - p)/(qf(x) + p)]
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
Trying to integrate: cos2x sin x dx Substitute y = cos x Then dy = -sin x dx So the integral becomes: -y2dy Integrating gives -1/3 y3 Substituting back: -1/3 cos3x