P = 2L + 2W Since L = 5W substitute into perimeter formula. P = 2*(5W) + 2W 10W + 2W = 40.8ft 12W = 40.8ft W = 3.4 ft
It is 12w.
Oh honey, solving for w in 2l + 2w = P is as easy as stealing candy from a baby. Just subtract 2l from both sides and then divide by 2. Voila, w = (P - 2l) / 2. Now go show off your math skills like the boss you are.
'W' and 'L' are independent variables. 'P' is the dependent variable. '2' and '2' are the constants.
(2, 1)
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
x = (P - 2W) / 2
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
P = 2L + 2W Since L = 5W substitute into perimeter formula. P = 2*(5W) + 2W 10W + 2W = 40.8ft 12W = 40.8ft W = 3.4 ft
It is: 6w-2
It is 12w.
-2w+14+10w=348w=20w=2.5
22
Stating our known facts Let W = Width, and L = Length L = 2W, and W = W+2 ----What you given is a never ending loop, saying that W always equals itself + 2. I will assume that you meant to put W = L+2 instead. Letting L = 2W and W = L + 2, we can state that x (the total area) is defined asL W(substituted so we're only working for one term)x = (2W)(2W + 2) Simplifyingx = 4W2 + 4W Since we are left with 2 variables, it can be stated that there is not enough information to solve the problem.