2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
P = 2L + 2W Since L = 5W substitute into perimeter formula. P = 2*(5W) + 2W 10W + 2W = 40.8ft 12W = 40.8ft W = 3.4 ft
It is 12w.
'W' and 'L' are independent variables. 'P' is the dependent variable. '2' and '2' are the constants.
(2, 1)
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5
x = (P - 2W) / 2
a = L x W: area equals length times the width. p = 2L + 2W: perimeter equals 2 times the length plus 2 times the width so L = (p - 2W)/2
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
2L+2W=P (S2w) Subtract 2W from both sides 2L=P-2W (D2) Divide both sides by 2 L=(P-2W)/2
2l + 2w = P Subtract 2l from both sides: 2w = P - 2l Divide both sides by 2: w = P/2 - l
P = 2L + 2W Since L = 5W substitute into perimeter formula. P = 2*(5W) + 2W 10W + 2W = 40.8ft 12W = 40.8ft W = 3.4 ft
It is: 6w-2
It is 12w.
-2w+14+10w=348w=20w=2.5
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