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3x - 3y = 12 ,,,, divide all equation on 3 ---> x - y = 4 .. Eq.1

4y - 8x = -16 ,,,, divide all equation on 4 ---> -2x + y = -4 .. Eq.2

by calculating the two eq. together the result will be :

x - 2x = zero

-x = zero

X = zero

Put the value of X, on Eq.1 to find the value of Y :

x - y = 4

zero - y = 4

Y = 4

Q: 3x - 3y equals 12 4y - 8x equals -16?

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(0,-4)

2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3

If 3y = 12, 2y = 8

5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6

4x + 3y = 12 3y = -4x + 12 y = -4/3x + 4 The slope is therefore -4/3 (the coefficient of the x term) The y intercept is 4 (the value of y when x = 0)

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(0,-4)

x = 12 and y = 8

The slope is -1. 3x+3y=12 Subtract 3x 3y=-3x+12 Divide by 3 y=-x+4

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4x+3y = 12 3y = -4x+12 y = -4/3x+4

(2, 2)

No.

Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!

(5, 1)

If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1

x = - 4 and y = 0

2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3