6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
(2x+3)(2x+4)
4x2-4x-120 = (2x+10)(2x-12) when factored
4x2 - 16x + 12
4x2 + 14x + 12 = 2(2x2 + 7x + 6) = 2(2x + 3)(x + 2)
4x2 plus 3=11
12
12
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
If you mean: x^2 +14x +24 then it is (x+2)(x+12) when factored
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
(2x+3)(2x+4)
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
-12
x2-14x+24=(x-12)(x-2) Since there are no options listed in this question ;), the answer could be either "x-12" or "x-2". How to factor a trinomial: see link.