124 (?) Try to do it on the calculator on your computer
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No, 4x2 + 14x + 12 is factorised, as follows:
4x2 + 14x + 12 = 2(2x2 + 7x + 6) = 2(x + 2)(2x + 3).
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6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
(2x+3)(2x+4)
4x2-4x-120 = (2x+10)(2x-12) when factored
4x2 - 16x + 12