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2 + y/4
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∙ 13y ago
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8 and y shared among 4 equals?
(8 + y) / 4 = 8/4 + y/4 = 2 + y/4
What is the difference of a number y cubed and 4 is less than the product of 8 and the number y?
abs(y^3 - 4) < 8*y
What is the equation of the line that contains the points 8 and 0 and 0 and 2?
Gradient = (2/-8) = -1/4So the general form of the equation is (y - 0) = -1/4*(x - 8)or y = -x/4 + 2that is x + 4y = 8Gradient = (2/-8) = -1/4So the general form of the equation is (y - 0) = -1/4*(x - 8)or y = -x/4 + 2that is x + 4y = 8Gradient = (2/-8) = -1/4So the general form of the equation is (y - 0) = -1/4*(x - 8)or y = -x/4 + 2that is x + 4y = 8Gradient = (2/-8) = -1/4So the general form of the equation is (y - 0) = -1/4*(x - 8)or y = -x/4 + 2that is x + 4y = 8
How do you find the slope and y-intercept for 2yequals 8?
2y = 8 y = 4 this is the equation of a horizontal line. The slope is 0, and the y-intercept is 4.
What is the value of 8 y-4 y when y 3?
when y = 3, 8y-4y = 4y = 4*3 = 12
8 and y shared among 4 equals?
(8 + y) / 4 = 8/4 + y/4 = 2 + y/4
What is a solution to these equations X plus Y equals -8 and 2x - y equals 4?
x+y=-8 2x-y=4 y=-x-8 2x+x+8=4 3x=-4 x=-4/3 -4/3 + y= -8 y = -8 + 4/3 y= -6 2/3
Find the value of 2 numbers if their sum is 12 and their difference is 4?
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4
What is the answer to x- y equals y if x equals 8?
For this problem, write it out... x-y=y... x=2y...8=2y...8/2=y...4=y First, I made both y's on the same side( I added a y to both sides). Then, I replaced the x with an 8. Then, I divide out the 2 from both sides. This leaves me with 4=y So... x=8, y=4, 8-4=4
What is the solution of y x 4 y 3x 8?
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
What is the value of y equals 2x when x equals 4?
y=8 y = 2x y = 2(4) <-- substitute 4 for x y = 8 <-- this is your answer
How do you solve y over 4 equals 10 over 8?
y/4 = 10/8 Multiply both sides by 4:- y = 40/8 y = 5
y-8=0/-8 (x+4)?
0/-8(x+4) = 0/(-8)(x+4) = 0/(-8x-32) y-8 = 0/(-8x-32) y = 8 + 0/(-8x-32 y = 8
Y equals 3x-4 and y equals 4 plus x solve by elimination?
y = 3x - 4 y = 4 + x Subtract the second equation from the first: y - y = 3x - 4 - 4 - x 0 = 2x - 8 2x = 8 so that x = 4 Substitute for x into second equation: y = 4 + 4 = 8 So the solutions is (4, 8).
How do you factor this x raised to the power of 8 y raised to the power of 8?
x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
-x+ 4 y>-8 x+y8 y?
-x+ 4y>-8, x+y≤3 y≤3-x -x+4(3-x)>-8 -x+12-4x>-8 12-5x>-8 -5x>-20 x>4 y≤3-(4) y≤-1
Solve for x and y when y equals 2x and 6x-y equals 8?
Cant do your own homework? this would be - 8=6x-2x 8=4x 8/4=x 2=x 6(2)-y=8 12-y=8 -y= (8-12) -y=-4 ---- multiply each by -1 to make positive y=4 test your work: 6(2)-4=8 ---- is this true? 12-4=8 8=8 - so your answer must be correct Seriously - do your own homework!
