I/you/we am 49
1
If the number with the digits reversed can have a leading 0 so that it is a 1-digit number, then 16. Otherwise 13.
So... the number has to be between 55 & 60 - and the sum of its digits must total 13... The only number that satisfies both rules is 58 !
I did it by trial and error. 7^2 is 49. 4 + 9 = 13
65
13
for new account its 13 digits...
65
Two.
There is only one possible combination of a 13 digit number created from 13 digits. In a combination, the order of the digits does not matter so that 123 is the same as 132 or 312 etc. If there are 13 different digits (characters) there is 1 combination of 13 digits 13 combinations of 1 or of 12 digits 78 combinations of 2 or of 11 digits and so on There are 213 - 1 = 8191 in all. If the characters are not all different it is necessary to have more information.
How about 7*7 = 49 because 4+9 = 13
13