Define the time (in days) taken by each person as: TA, TB and TC. In one day, A, B and C can respectively complete the following proportions of the work: 1/TA, 1/TB and 1/TC So together, they complete 1/TA + 1/TB + 1/TC of the work. It follows that they take 1 / [1/TA + 1/TB + 1/TC] days to complete the job together. So we can write * 6 = 1 / [1/TA + 1/TB + 1/TC] And by similar arguments: * 9 = 1 / [1/TB + 1/TC] * 8 = 1 / [1/TA + 1/TC] Solve the three equations simultaneously: * 1/6 = 1/TA + 1/TB + 1/TC * 1/9 = 1/TB + 1/TC subtracting yields 1/6 - 1/9 = 1/TA 1/TA = 1/18 * 1/9 = 1/TB + 1/TC * 1/8 = 1/18 + 1/TC subtracting yields 1/8 - 1/9 = 1/18 - 1/TB 1/TB = 1/9 - 1/8 + 1/18 = 3/72 = 1/24 and finally 1/TC = 1/8 - 1/18 = 5/72 Thus: TA = 18, TB = 24, TC =72/5.
'A' can do the job in 20 days. He does (1/20th) of the job in 1 day. After 4 days, he finished(4/20ths) of the job, and there were (16/20ths) remaining. That's when 'B' came along.'B' finished the (16/20ths) of the job in 16 days, so 'B' also does (1/20th) of the job each day.If they work together from the beginning of a new job, they do (1/20 + 1/20) = 2/20 = 1/10thof the job each day, and it takes them 10 days to do the whole thing together.
There are 30 working days in six weeks.
A does 1/6 of the work in 1 day. B does 1/4 of the work in 1 day. Assuming there is no synergy, A and B, together do 1/6 + 1/4 = 5/12 of the work in 1 day A worked for 2 days so completed 2*(1/6) = 1/3 of the work. So 2/3 of the work remained to be done by A and B together. They would do it in (2/3) / (5/12) = (2/3) * (12/5) =24/15 = 8/5 = 1.6 days. The total time to finish the work is 2 days + 1.6 days = 3.6 days.
Use ratios, 20/15 = 25/x Multiply 15 by 20, then divide by 25. So 25 men could finish a job in 12 days.
Double the men, halve the time. So 12 men will do it in one day.
-- B can do the job alone in 16 days.-- So B does 1/16 of the job per day.-- In 6 days, B does 6/16 = 3/8 of the job.-- If A and B working together do the job in 6 days, then A does the other 5/8 of the job in 6 days.-- So A does 5/48 of the job each day.-- If they begin together, then after 3 days, A has done 5/16 and B has done 3/16.Together, they've finished 8/16 = 1/2 of the job. Not so surprising, when we recallthat it takes them 6 days to do the whole thing together.-- Half of the job then remains for A to finish on his own. Since he does 5/48 per day,he needs 24/5 = 4.8 days to finish off the last half.4.8 more days
The whole job takes 16 days.If you carve up the job into 48 pieces, then (48/16) = 3 pieces were done each day,of which 'A' did 2 pieces and 'B' did 1 piece.Since 'A' does 2 pieces of work a day, and a whole job consists of 48 pieces,it takes him (48/2) = 24 days to do the whole job alone.
A & B together do 1/6 in 1 day. A alone does 1/9 in 1 day so in 1 day B does (1/6 - 1/9) ie 1/18 so would take 18 days on his own.
As he got his company put together, he hired workers but at the end of his days he worked alone.
10 tasks x 5 days per task = 50 days
225 days
You will need a total of 50 days to complete the project.
'A' can do the job in 20 days. He does (1/20th) of the job in 1 day. After 4 days, he finished(4/20ths) of the job, and there were (16/20ths) remaining. That's when 'B' came along.'B' finished the (16/20ths) of the job in 16 days, so 'B' also does (1/20th) of the job each day.If they work together from the beginning of a new job, they do (1/20 + 1/20) = 2/20 = 1/10thof the job each day, and it takes them 10 days to do the whole thing together.
A does 1/10 per day on his own, so in 6 days he's done 60%, leaving 40% done by B in 6 days. B will take 6 x 100/40 days on his own, ie 15 days
It might have been possible to answer the question is you had had the time to complete the question!
If a man working 6 hours per day can complete a piece of work in 12 days, the total work done is 6 hours/day × 12 days = 72 hours. To finish the same work in 8 days, he needs to work 72 hours ÷ 8 days = 9 hours per day. Therefore, he must work 9 hours per day to complete the task in 8 days.
First. Let the two cats stay together. Then after a few days keep an eye on them. If you see them sitting together, Brushing fur together, eating together and so on, They will probably start mating!!