Take acceleration of gravity = 9.8 m/s2 .
The ball stops rising and starts falling in (100/9.8) seconds.
It returns to the height of the bat in 2 x (100/9.8) = 20.408 seconds. (rounded)
20.40
The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
a small airplane flies in a straight line at a average speed of 150 km/hour .how long dose it take the plane to fly 250 km
Assuming that air resistance can be ignored, s = ut + 0.5gt2 where s is the distance travelled = 324 feet, u is the initial velocity = 0 ft/sec, t is the time (in seconds), and g is the acceleration due to gravity = 32 ft/sec2 Therefore 324 = 0.5*16*t2 so that t2 = 20.25 and so t = 4.5 seconds.
It all depends on the initial velocity at which you fell, and whether air resistence is present, etc. If you are simply in a state of free fall, your time to reach the ground would be d=100m v1=0 a=9.8 <- acceleration of gravity on earth t=unknown d = Vi*t + 1/2 a t^2 100m=0*t+1/2(9.8) *t^2 100m=4.9*t^2 sqrt:(100m/4.9)=t
20.40
This is a velocity question so u need to use uvaxt
51 seconds.
initial velocity of the kick = 28.06 m/s
The object's initial distance above the ground The object's initial velocity
The answer will depend on what "it" is, and on what its initial velocity is.
In a vacuum it would fall back to the same height at the same speed, 150m/s. It would then gain another minuscule fraction of speed as it fell from bat-height down to the ground. In the real world, a falling baseball will reach a maximum speed of around 42 meters per second because the air resistance slows it down. This is called Terminal Velocity.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
To answer this question one would need to know the rock's initial height and velocity.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
I assume you hit it up from the ground level as well. From Conservation of Energy, it immediately follows that: * If there is no air resistance, when it hits the ground it will, once again, have a speed of 100 meters per second. * Since under usual circumstances there WILL BE air resistance, its speed will be less than 100 meters per second.