#include <iostream>
using namespace std;
int main()
{
int x, y, z;
cout << "Enter 3 numbers: \n";
cin >> x;
cin >> y;
cin >> z;
if(x < y && x < z)
{
cout << x << " ";
if(y < z)
{
cout << y << " " << z;
}
else if(z < y)
{
cout << z << " " << y;
}
}
else if(y < x && y < z)
{
cout << y << " ";
if(x < z)
{
cout << x << " " << z;
}
else if(z < x)
{
cout << z << " " << x;
}
}
else if(z < y && z < x)
{
cout << z << " ";
if(y < x)
{
cout << y << " " << x;
}
else if(x < y)
{
cout << x << " " << y;
}
}
char wait;
cin >> wait;
return 0;
}
In that case, unless you specifically convert ("cast") at least one of the numbers to a double or float, the result will also be an integer. Example: 1 / 3 = 0
Use %o
#include<stdio.h> #include<conio.h> void main() { int a[10],count_even=0,count_odd=0,neg=0,i; printf(" Enter the value in Array \n"); for(i=0;i<10;i++) scanf("%d", &a[i]); /* Calculating number of odd and even integer's */ for(i=0;i<10;i++) { if((a[i]%2 ==0)) count_even++; if((a[i]%2==1)) count_odd++; if(a[i]<0) neg++; } /* display the number of odd and even integer's */ printf(" Total number of even integer are %d\n ",count_even); printf("Total number of odd integer are %d\n", count_odd); printf(" Total negative integer are %d", neg); getch(); }
write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
write an assembly language program to find sum of N numbers
sorry
In that case, unless you specifically convert ("cast") at least one of the numbers to a double or float, the result will also be an integer. Example: 1 / 3 = 0
the following program will display all numbers given in the array in ascending order #include<stdio.h> void main() { int i,h,p; int numbers[10]={5,8,3,2,6,7,9,4,1,10}; for(p=0;p<=8;p=p+1) { for(i=0;i<=8;i=i+1) { if(numbers[i]>numbers[i+1]) { a=numbers[i]; numbers[i]=numbers[i+1]; numbers[i+1]=a; } } } for(i=0;i<=9;i=i+1) { printf("%d ",numbers[i]); } }
To write a C++ program to display the student details using class and array of object.
To arrange numbers in ascending order using Java, you can utilize the Scanner class to read input from the user and then sort the numbers using an array. Here's a simple example: import java.util.Arrays; import java.util.Scanner; public class AscendingOrder { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter the number of elements: "); int n = scanner.nextInt(); int[] numbers = new int[n]; System.out.println("Enter the numbers:"); for (int i = 0; i < n; i++) { numbers[i] = scanner.nextInt(); } Arrays.sort(numbers); System.out.println("Numbers in ascending order: " + Arrays.toString(numbers)); scanner.close(); } } This program collects a specified number of integers from the user, sorts them using Arrays.sort(), and then displays the sorted list.
I know how to do this and you need to know how to do this. Why don't you do your best at writing this program and if it does not work then ask for help. You will not learn anything if I give you the answer.
The following is for F95 and later (due to the use of intrinsic SUM ): My assumptions: -Your numbers are integers -Your numbers are stored in an array -The numbers you are describing are 0-100 program findSum !I assumed integer, replace this with your data type integer, dimension(100) :: numbers integer :: sumOfNumbers !We populate an array with our numbers !Replace this with your numbers do i=1,(size(numbers)+1) numbers = i end do !We find the sum of those numbers sumOfNumbers = sum(numbers) !We write out the sum to prompt write(*,*) 'Sum is: ', sumOfNumbers end program findSum
#include<iostream> int main() { for (int i=0; i<100; ++i) std::cout<<i<<std::endl; }
The simplest would be to put the numbers into an int[] (integer array) and pass that to java.util.Arrays.sort(int[]) (a static method), which will sort the array in ascending numerical order. Use a float[] or double[] if you need to sort non-whole numbers. You can also use the Collections.sort(List) method to sort the List directly. Or the Collections.sort(List, Comparator) if you wish to specify your own sorting criteria.
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
$n = 10*(1+10)/2;
In Visual Basic .NET, you can create a simple program to add two numbers by using input boxes or text fields to gather user input. For example, you would declare two variables to store the numbers, convert the input to numeric types, and then perform the addition. Finally, you can display the result using a message box or a label. Here's a basic example: Dim num1 As Integer = Convert.ToInt32(InputBox("Enter first number:")) Dim num2 As Integer = Convert.ToInt32(InputBox("Enter second number:")) Dim sum As Integer = num1 + num2 MessageBox.Show("The sum is: " & sum)