-- Mr. A. can complete the job in 12 days.
-- He does 1/12 of the job in 1 day.
-- Mr. B. is 60% as efficient as Mr. A. is.
-- Mr. B. does (60% of 1/12) = 0.6/12 = 1/20 of the job in 1 day.
-- It takes Mr. B. 20 days to do the same work.
Q can do the work in 6 days. ( Time taken by P will be more than Q i.e their time ratio will be 150:100 and this is to 9:x, or 150:100::9:X which will give value of X as 6)
4 men are required
12 days
Using logic, if it takes 14 days for 6 men to complete the task, then it would take 3 men 28 days. Continuing it would take one man84 days (3 x 28) to complete. So, now moving backwards, it would take 2 men 42 days (half of the 84) and 4 en 21 days (half of 42)
5% decrease
It might have been possible to answer the question is you had had the time to complete the question!
Q can do the work in 6 days. ( Time taken by P will be more than Q i.e their time ratio will be 150:100 and this is to 9:x, or 150:100::9:X which will give value of X as 6)
10.5 days how it comes : if a is twice as efficient than b that means ratio of time taken by A and B is :- 1:2 then 1/2x + 1 /x = 7 x=10.5
4 men are required
In 4 days!
2 days out of 5 - is 40 percent
12 days
2.5 percent of 30 days is 0.75 days or 18 hours.
It takes 365 days to complete it.
They will take 4 days to complete the well.
There are 17 complete weeks in 125 days.
Using logic, if it takes 14 days for 6 men to complete the task, then it would take 3 men 28 days. Continuing it would take one man84 days (3 x 28) to complete. So, now moving backwards, it would take 2 men 42 days (half of the 84) and 4 en 21 days (half of 42)