Using logic, if it takes 14 days for 6 men to complete the task, then it would take 3 men 28 days. Continuing it would take one man84 days (3 x 28) to complete. So, now moving backwards, it would take 2 men 42 days (half of the 84) and 4 en 21 days (half of 42)
4 men are required
9 days a week
Q can do the work in 6 days. ( Time taken by P will be more than Q i.e their time ratio will be 150:100 and this is to 9:x, or 150:100::9:X which will give value of X as 6)
-- Mr. A. can complete the job in 12 days.-- He does 1/12 of the job in 1 day.-- Mr. B. is 60% as efficient as Mr. A. is.-- Mr. B. does (60% of 1/12) = 0.6/12 = 1/20 of the job in 1 day.-- It takes Mr. B. 20 days to do the same work.
Tomorrow will be 3 days
4 men are required
10 kindly do the steps
What a Piece of Work I Am has 275 pages.
6 boys and 15 girls can do a piece of work in 4 days while 12 boys 3 girls do the same work in 5 days. In how many days will 1 boy and 1 girl do the work seperately ?
It might have been possible to answer the question is you had had the time to complete the question!
If a "certain number of men" less 10 takes 20 days (twice as long) to finish the piece of work, then the "certain number of men" who can finish the work in 10 days would 20. If it takes 10 men less twice as long to do the work, then twice 10 men (20) can finish the job in 10 days.
A piece of software program does not make sense because a whole program is needed to work.
In 4 days!
25 men in 32 days do 25*32 = 800 man-days of word. If you have 20 men, they would take 800/20 = 40 days.
It depends on how many days a week they have to work.
208 days
260 days.