4 men are required
Using logic, if it takes 14 days for 6 men to complete the task, then it would take 3 men 28 days. Continuing it would take one man84 days (3 x 28) to complete. So, now moving backwards, it would take 2 men 42 days (half of the 84) and 4 en 21 days (half of 42)
-- Mr. A. can complete the job in 12 days.-- He does 1/12 of the job in 1 day.-- Mr. B. is 60% as efficient as Mr. A. is.-- Mr. B. does (60% of 1/12) = 0.6/12 = 1/20 of the job in 1 day.-- It takes Mr. B. 20 days to do the same work.
2 Days. 2 people x 5 days = 10 days of work. 10 days / 5 people=2 days
I think you need an extra 4 workers (assuming each worker works the same amount as all the other workers).
One piece will suffice.
It might have been possible to answer the question is you had had the time to complete the question!
Using logic, if it takes 14 days for 6 men to complete the task, then it would take 3 men 28 days. Continuing it would take one man84 days (3 x 28) to complete. So, now moving backwards, it would take 2 men 42 days (half of the 84) and 4 en 21 days (half of 42)
It takes 365 days to complete it.
earth takes 365 days to complete it
17 weeks and 6 days
They will take 4 days to complete the well.
About 4,280 earth days.
88 days
11 to 12 quarts for a complete overhaul ...
Two complete revolutions.
5 workers are needed for 12 days, hence each day 5/12 worker is needed. If we assume the same efficiency, then this same rate must be maintained by workers over 3 days. Hence 5/12 = 3/x or 5x = 36, x = 7 and 1/5, so we need at least 8 workers since 1/5 worker is not possible.
How many of 0.325 are needed to complete hydrolyze (saponify) 2.800 ethyl octanoate?