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20 coins, consisting of dimes and quarters.

if the values were switched, the difference would be 90 cents.

This is how i came up with my answer.

solving the system:

one equation describes the number of coins: x + y = 20

where x is the number of dimes and y is the number of quarters.

the other equation describes the amount of money:

(0.25x + 0.1y) - (0.1x + 0.25y) = 0.90

(0.25x + 0.1y) describes when the dimes are quarters and the quarters are dimes.

(0.1x + 0.25y) describes when the dimes and quarters are their original values.

The difference is supposed to be $0.90 or 90cents.

Therefore,

by the elimination method of solving a system of equations:

x + y = 20 #1

(0.25x + 0.1y) - (0.1x + 0.25y) = 0.9 #2

simplify #2 to become:

0.15x - 0.15y = 0.9 #3

x + y = 20 #1

0.15x - 0.15y = 0.9 #3

multiply #1 by 0.15:

0.15x + 0.15y = 3 #4

0.15x - 0.15y = 0.9 #3

add #4 and #3:

0.30x = 3.9

x = 13

therefore, the number of dimes that the man has is 13.

to find the number of quarters, x is evaluated in the 1st equation.

x + y = 20

13 + y = 20

y = 20 - 13

y = 7

This can be checked as follows.

13 dimes = 130 cents

7 quarters = 175 cents

total = 305 cents

13 quarters = 325 cents

7 dimes = 70 cents

total = 395 cents

The difference between the two is 90 cents.

Therefore, the man had 13 dimes and 7 quarters.

By the way, is this a question that you are doing in class, have the answer to and are seeing who can figure it out, or are you proposing it for another reason?

Addendum (by PatrickLMT): Actually, this question was featured in the February 26, 1974 comic strip "Peanuts." Peppermint Patty had this question in school and despaired of finding the answer.

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