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B = boatspeed

C = current speed

6 (B-C) = 558

8 (B+C) = 1,016

Eliminate parentheses:

6B - 6C = 558

8B + 8C = 1,016

Divide both sides of the first equation by 6.

Divide both sides of the second equation by 8.

B - C = 93

B + C = 127

Add the equations:

2B = 220

B = 110 kph

Subtract the equations:

-2C = -34

C = 17 kph

The current is rather speedy, and the boat even speedier ... 68.3 mph in still water ! ! !

Suspicious vis a vis the real world, but the math is bullet-proof.

Q: A motorboat travels 558 km in 6 hours going upstream and 1016 km in 8 ours going downstream What is the rate of the boat in still water and what is the rate of the current?

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Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH

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Related questions

The current flows at 4 kph.The boat motors at 11 kph.

Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH

The speed upstream is B - C where B is the speed of the badge in still water and C is speed of the current The speed downstream is B + C. Velocity = Distance/Time : therefore Time = Distance/Velocity. Time for upstream journey = 6/(B - C) Time for downstream journey = 6/(B + C) BUT Total time for journey = 2 = 6/(B - C) + 6/(B + C) = 12B/(B2 - C2) Therefore 2B2 - 2C2 = 12B : However, B = 8kph so substituting gives, 128 - 2C2 = 96 : 2C2 = 32 : C2 = 16 : C = 4 The speed of the current is 4kph.

Anything with a face should be looking inward and almost never outwards, and with Koi, they ALWAYS go upstream and never downstream.

By definition all rivers run downstream, with the possible exception of tidal effects where the river meets the sea (as the tide comes in, in some places the water may run "backward" up the river for a usually short distance).

89 ft

upstream

Suppose the speed of the boat is x mph. Then upstream, it travels 5 hours at x-3 mph and so covers 5x - 15 miles. When going downstream the boat covers the same distance, at x+3 mph, in 2.5 hours so (5x-15)/(x+3) = 2.5 Multiply through by 2*(x+3): 2*(5x-15) = 5*(x+3) 10x - 30 = 5x + 15 or 5x = 45 giving x = 9 mph.

Downstream

To get to his parents house John must travel at a speed of 60 mph on land and then use a motorboat that travels at a speed of 20 mph in still water John goes by land to a dock and then travels 138 miles.

7/12 kmph

The maximum speed that a vessel will achieve relative to ground is its own maximum speed through water plus the speed of the the moving water downstream.