B = boatspeed
C = current speed
6 (B-C) = 558
8 (B+C) = 1,016
Eliminate parentheses:
6B - 6C = 558
8B + 8C = 1,016
Divide both sides of the first equation by 6.
Divide both sides of the second equation by 8.
B - C = 93
B + C = 127
Add the equations:
2B = 220
B = 110 kph
Subtract the equations:
-2C = -34
C = 17 kph
The current is rather speedy, and the boat even speedier ... 68.3 mph in still water ! ! !
Suspicious vis a vis the real world, but the math is bullet-proof.
Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
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Anything that travels 1,635 miles per hour.
27
what is the speed of a rocket that travels 9000 meters in 12.12 seconds
The current flows at 4 kph.The boat motors at 11 kph.
Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
The speed upstream is B - C where B is the speed of the badge in still water and C is speed of the current The speed downstream is B + C. Velocity = Distance/Time : therefore Time = Distance/Velocity. Time for upstream journey = 6/(B - C) Time for downstream journey = 6/(B + C) BUT Total time for journey = 2 = 6/(B - C) + 6/(B + C) = 12B/(B2 - C2) Therefore 2B2 - 2C2 = 12B : However, B = 8kph so substituting gives, 128 - 2C2 = 96 : 2C2 = 32 : C2 = 16 : C = 4 The speed of the current is 4kph.
Anything with a face should be looking inward and almost never outwards, and with Koi, they ALWAYS go upstream and never downstream.
By definition all rivers run downstream, with the possible exception of tidal effects where the river meets the sea (as the tide comes in, in some places the water may run "backward" up the river for a usually short distance).
If the boat is moving downstream, you add the speed of the boat with the speed of the river flow. Therefore, the velocity of the boat downstream is 18 km/h. If the boat is moving upstream, you subtract the river flow speed from the boat's speed, so in this case, it would be 12 km/h.
89 ft
upstream
Suppose the speed of the boat is x mph. Then upstream, it travels 5 hours at x-3 mph and so covers 5x - 15 miles. When going downstream the boat covers the same distance, at x+3 mph, in 2.5 hours so (5x-15)/(x+3) = 2.5 Multiply through by 2*(x+3): 2*(5x-15) = 5*(x+3) 10x - 30 = 5x + 15 or 5x = 45 giving x = 9 mph.
Downstream
To get to his parents house John must travel at a speed of 60 mph on land and then use a motorboat that travels at a speed of 20 mph in still water John goes by land to a dock and then travels 138 miles.
7/12 kmph