Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
The resultant velocity of a boat is 17 km/hr and the direction of the boat is SW.
2.2 Type your answer here...
ans is = 10 - 8 = 2 m/s (upstream)
Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
If the boat is moving downstream, you add the speed of the boat with the speed of the river flow. Therefore, the velocity of the boat downstream is 18 km/h. If the boat is moving upstream, you subtract the river flow speed from the boat's speed, so in this case, it would be 12 km/h.
7/12 kmph
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
The current flows at 4 kph.The boat motors at 11 kph.
The resultant velocity of a boat is 17 km/hr and the direction of the boat is SW.
assume river velocity = X mph boat velocity = 20 mph time to go 6 miles downstream = T1 time to go 3 miles upstream = T2 distance = time * velocity downstream: 6 mi = T1 * (boat velocity + river velocity) upstream: 3 mi = T2 * (boat velocity - river velocity) 6 = T1 * ( 20 + X ) 3 = T2 * ( 20 - X ) T1 * ( 20 + X ) = 2 * ( T2 * ( 20 - X ) ) since T1 = T2 then 20 + X = 40 - 2X 3X = 20 X = 6.67 thus, river velocity is 6.67mph
If the boat is moving upstream at the same speed as the current moving downstream, the boat will appear to be stationary relative to an observer on the shore. This is because the boat's upstream motion is being cancelled out by the downstream motion of the current.
Let the velocity in still water be V and the current be U. The net velocity upstream (against the current) is 20/6 = V - U . The net velocity downstream is ,18/4 = V + U. Add the equations to get 7.83 = 2V . Subtract the equations to get, 1.17 = 2U. So, V= 3.91 and U = .58
Suppose the speed of the boat is x mph. Then upstream, it travels 5 hours at x-3 mph and so covers 5x - 15 miles. When going downstream the boat covers the same distance, at x+3 mph, in 2.5 hours so (5x-15)/(x+3) = 2.5 Multiply through by 2*(x+3): 2*(5x-15) = 5*(x+3) 10x - 30 = 5x + 15 or 5x = 45 giving x = 9 mph.
The distance traveled by the boat can be calculated using the formula Distance = Velocity x Time. Plugging in the values, the distance would be 1.55 m/s x 246 seconds, which equals 380.7 meters.
upstream