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Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
The resultant velocity of a boat is 17 km/hr and the direction of the boat is SW.
2.2 Type your answer here...
ans is = 10 - 8 = 2 m/s (upstream)
Boat WRT land, downstream 10 + 8 = 18 KMH Boat WRT land, upstream 10 - 8 = 2 KMH Boat WRT water 10 KMH
7/12 kmph
Velocity = Distance ÷ Time.The speed upstream = 300 ÷ 5 = 60kph.The speed downstream = 300 ÷ 2 = 150 kph.The speed upstream equals boat velocity(Vb) minus current velocity(Vc).The speed downstream equals boat velocity (Vb) pluscurrent velocity (Vc).Vb - Vc = 60Vb + Vc = 150 : Adding the two equations together gives :-2Vb = 210 : Vb = 105, therefore Vc = 45The rate of the boat in still water is 105 kph. The rate of the current is 45 kph.
The resultant velocity of a boat is 17 km/hr and the direction of the boat is SW.
The current flows at 4 kph.The boat motors at 11 kph.
assume river velocity = X mph boat velocity = 20 mph time to go 6 miles downstream = T1 time to go 3 miles upstream = T2 distance = time * velocity downstream: 6 mi = T1 * (boat velocity + river velocity) upstream: 3 mi = T2 * (boat velocity - river velocity) 6 = T1 * ( 20 + X ) 3 = T2 * ( 20 - X ) T1 * ( 20 + X ) = 2 * ( T2 * ( 20 - X ) ) since T1 = T2 then 20 + X = 40 - 2X 3X = 20 X = 6.67 thus, river velocity is 6.67mph
Let the velocity in still water be V and the current be U. The net velocity upstream (against the current) is 20/6 = V - U . The net velocity downstream is ,18/4 = V + U. Add the equations to get 7.83 = 2V . Subtract the equations to get, 1.17 = 2U. So, V= 3.91 and U = .58
Suppose the speed of the boat is x mph. Then upstream, it travels 5 hours at x-3 mph and so covers 5x - 15 miles. When going downstream the boat covers the same distance, at x+3 mph, in 2.5 hours so (5x-15)/(x+3) = 2.5 Multiply through by 2*(x+3): 2*(5x-15) = 5*(x+3) 10x - 30 = 5x + 15 or 5x = 45 giving x = 9 mph.
upstream
2.2 Type your answer here...
You mean, travels at 10000 m/s.....if so...Its velocity is 10000m/s
if the boat turns toward the dock without going upstream, it will miss it's mark because the current is pushing the boat downstream.