2s-2b= a+b+c-2b simplified that would be a+c-b.
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
The simplified answer is: 4c+2b
c-2b
2b + 2c or 2(b + c)
a + 2b = c a = c - 2b
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
a = 2b + c then a - 2b = c ie c = a - 2b
2s-2b= a+b+c-2b simplified that would be a+c-b.
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
If 2b a plus c, then we can say that 3tan A 2tan c = 21.
The simplified answer is: 4c+2b
c-2b
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
c= a-2b
a-2b=c
ac - 3ad - 2bc + 6bd = a(c - 3d) - 2b(c - 3d) = (a - 2b)(c - 3d)