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A point P is at a distance of square root 10 units from the point 4 and 3 Find the coordinates of the point P if its ordinate is twice of its abscissa?
'P' located at the point (x,y), and y = 2x. (ordinate = abcissa x 2) Distance of 'P' from (4,3) is square root of 10. (Distance)2 of 'P' from (4,3) is 10. ( x - 4 )2 + ( y - 3 )2 = 10 x2 - 8x + 16 + y2 - 6y + 9 = 10 x2 - 8x + y2 - 6y + 15 = 0 But y = 2x, so x2 - 8x +(2x)2 -6(2x) +15 = 0 5x2 - 20x + 15 = 0 ===> x2 - 4x + 3 = 0 ( x - 3 )( x - 1 ) = 0 x = 3 and x = 1 y = 6 and y = 2 The point 'P' can be either (3,6) or (1,2). Both points satisfy the given conditions.
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What is the distance between the points -2 5 and 3 -4?
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
What are the coordinates of a square?
2,1 6,1 2,5 and
The coordinates of A and B are 27 square root and 15 square root respectively Find AB?
It takes two coordinates to locate one point, but you've given only two numbers to locate two points. The distance between them can't be calculated with the information given, because the points can't be identified.
The coordinates of a and b are square root of 27 and square root of 15 reapectively find ab?
Find ab
How do you solve for the abscissa in a unit circle if the ordinate is given?
abscissa = sqrt[1 - square of the ordinate]
Formula to find distance in co-ordinate geometry?
D=(x2-x1)2 + (y2-y1)2then square root the number that you get
What is the distance between the two points in simplest radical form?
The distance between two points is Square root of [ (difference in their 'x' coordinates)2 + (difference in their 'y' coordinates)2 ]
What is the formula for the distance between two coordinates on a grid?
Distance= The Square Root of: (x1- X2)2 + (Y1- Y2)2
What is the distance between the points -2 5 and 3 -4?
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
How can one determine the distance between two points on a graph using the keyword "how to find distance on a graph"?
To determine the distance between two points on a graph, you can use the distance formula, which is derived from the Pythagorean theorem. This formula calculates the distance as the square root of the sum of the squares of the differences in the x-coordinates and y-coordinates of the two points. By plugging in the coordinates of the two points into the formula, you can find the distance between them on the graph.
How many quadrants are there on a square coordinate system?
There are four quadrants in a square co-ordinate system.
What is the distance between 5 -2 and 10 5?
Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
How do you find the distance between two coordinates in geometry?
square root(x2-x1)squared+(y2-y1)squared
What is the distance between -7 5 and -6 -4?
The idea is to use the Pythagorean theorem: take the square root of (square of the difference in x-coordinates + square of the difference in y-coordiantes).
Find the distance between the points -10 8 and -2 -7?
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
What is the formula of converting co ordinates to distance?
It is the square root of: (x1-x2)2+(y1-y2)2 for a given pair of coordinates
