Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
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The distance between (10, 5) and (5, -2) is sqrt[(10 - 5)2 + (5 + 2)2] = sqrt(52 + 72) = sqrt(25 + 49) = sqrt(74) = 8.602 (to 3 dp)
(Distance)2 = (2 - 5)2 + (6 - 2)2
Distance is sq rt ((x2-x1)2+((y2-y1) So 9+1 is 10. sqrt of 10 is 3.16 distance rounded to hundredths
-2 & 5
(2-5)2+(5-7)2 = 13 and the square root of this is the distance which is about 3.60555 to 5 decimal places