Please use the Pythagoran property: calculate the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
The distance between (10, 5) and (5, -2) is sqrt[(10 - 5)2 + (5 + 2)2] = sqrt(52 + 72) = sqrt(25 + 49) = sqrt(74) = 8.602 (to 3 dp)
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
(Distance)2 = (2 - 5)2 + (6 - 2)2
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Distance is sq rt ((x2-x1)2+((y2-y1) So 9+1 is 10. sqrt of 10 is 3.16 distance rounded to hundredths
The distance between (10, 5) and (5, -2) is sqrt[(10 - 5)2 + (5 + 2)2] = sqrt(52 + 72) = sqrt(25 + 49) = sqrt(74) = 8.602 (to 3 dp)
If you mean points of (5, 5) and (1, 5) then the distance is 4
It is the square root of: (5-5)2+(6-2)2 = 4
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
You could write them out to show the distance on the numberline-5 -4 -3 -2 -1 0 +1 +2 +3 +4 +5or subtract minus 5 from 55 - -5 = 10
(Distance)2 = (2 - 5)2 + (6 - 2)2
distance = sqrt( (xf-xi)2 + (yf-yi)2 ) = sqrt( ((-3) - (1))2 + ((5) - (-1))2 ) = sqrt(52)
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Distance is sq rt ((x2-x1)2+((y2-y1) So 9+1 is 10. sqrt of 10 is 3.16 distance rounded to hundredths
Points: (2, 4) and (5, 0) Distance: 5
-2 & 5