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Q: A quadratic equation in standard form is written ax2 plus bx equals c where a b and c are real numbers and a is not zero?

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The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.

They are page numbers 24 and 25 . ( 24 x 25 = 600 ) The easiest way to solve this is by trial and error. Multiply two consecutive numbers; if the product is too low, try larger numbers, if it is too high, try smaller numbers. You can also write an equation and use the quadratic formula. The equation in this case is x(x+1) = 600. Re-written for use of the quadratic equation, it becomes x2 + x - 600 = 0. This will give you a positive and a negative solution; only the positive solution is sensible in this case.

The way you wrote it is the standard notation. Standard notation means to write the number in its standard form. So, a number such as 150 is simply written as 150 in standard notation. The same applies to decimals.

This is a basic quadratic equation. The question must be regarded as, How do you factor x² - 36 = 0 ? This equation can be written as x² - 6² = 0, which factors as (x + 6)(x - 6) = 0 This leads to the solutions (or roots) x = -6 and x = 6, often written as x = ±6

If the quadratic function is written as ax2 + bx + c, then it has no x-intercepts if the discriminant, (b2 - 4ac), is negative.

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The quadratic equation, in its standard form is: ax2 + bx + c = 0 where a, b and c are constants and a is not zero.

ax2 + bx + c = 0

The quadratic formula is used to solve the quadratic equation. Many equations in which the variable is squared can be written as a quadratic equation, and then solved with the quadratic formula.

Yes that about sums it up.

it is 1

George E. Forsythe has written: 'What is a satisfactory quadratic equation solver?' 'Finite-difference methods for partial differential equations' 'How do you solve a quadratic equation?'

Without an equality sign the given terms of an algebraic expression can't be classed as an equation and so therefore a solution is not possible.

It is: x2-10x+21 = 0 and the value of x is 3 or 7 when solved

It is: 3x2-5x-2 = 0 and the value of x is -1/3 or 2 when solved

There are many ways: one is to factorise. If the quadratic is written as ax2 + bx + c then, if b2 = 4ac, the quadratic is a perfect square. It is (x - b/2a)2

They are page numbers 24 and 25 . ( 24 x 25 = 600 ) The easiest way to solve this is by trial and error. Multiply two consecutive numbers; if the product is too low, try larger numbers, if it is too high, try smaller numbers. You can also write an equation and use the quadratic formula. The equation in this case is x(x+1) = 600. Re-written for use of the quadratic equation, it becomes x2 + x - 600 = 0. This will give you a positive and a negative solution; only the positive solution is sensible in this case.

A quadratic equation is an equation where a quadratic polynomial is equal to zero. It can be written as ax^2+bx+c=0 where a,b,c are the coefficients and x is the variable. A quadratic equation has always two complex solutions for x given by the formula x=-b/2a+sqrt(b^2-4ac)/2a and x=-b/2a-sqrt(b^2-4ac)/2a. Examples of quadratic equations are x^2+x-2=0, 5x^2+6x=0, x^2+1=0 etc.

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