This is a basic quadratic equation.
The question must be regarded as, How do you factor x² - 36 = 0 ?
This equation can be written as x² - 6² = 0, which factors as (x + 6)(x - 6) = 0
This leads to the solutions (or roots) x = -6 and x = 6, often written as x = ±6
x2-5x-36 = (x-9)(x+4) when factored
(x + 6)(x - 6)
(x + 12)(x - 3)
(5x - 6)(5x + 6)
(6x - 1)(6x - 1)
2x^(2) + 72 Factors to 2( x^(2) + 36) s(x^(2) + 6^(2)) Does NOT factor. NB Remember . two squared terms with a positive(+) between them does NOT factor!!!! However, two squared terms with a negative(-) between DOES factor . e.g. x^(2) + 6^(2) Does NOT factor x^(2) - 6^(2) factors to ( x - 6)( x + 6 ) Note the different signs. Similarly 8^(2) + 6^(2) does NOT factor 8^(2) - 6^(2) factors to (8 - 6)(8 + 6) Or using the ~Pythagorean Equation. h^(2) = a^(2) + b^(2) Does NOT factors However, a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b) .
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x(x-1)
(x + 2)(x - 9)
(x - 5)(x + 3)
(x + 2)(x - 4)