This is a basic quadratic equation.
The question must be regarded as, How do you factor x² - 36 = 0 ?
This equation can be written as x² - 6² = 0, which factors as (x + 6)(x - 6) = 0
This leads to the solutions (or roots) x = -6 and x = 6, often written as x = ±6
x2-5x-36 = (x-9)(x+4) when factored
(x + 6)(x - 6)
(x + 12)(x - 3)
(5x - 6)(5x + 6)
(6x - 1)(6x - 1)
x sq equalls 36 and x equalls plus or minus 6
x 2 - 5x - 36 = 0; factor. (x-9)(x+4) = 0; set each factor = 0. x - 9 = 0 and x + 4 = 0 So, x = 9 and x = -4.
9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)
x(x-1)
(x + 2)(x - 4)
(x + 2)(x - 9)
(x - 5)(x + 3)