10cm x 7cm x 12cm =840 square cm3
200 sq. cm.
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
The area defined by the above measurements is 70 square centimeters.
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
It is: 10*10 = 100 square cm
A "square" is a figure that has four sides of equal length. To get its perimeter, you multiply any of the four sides by 4. If you mean a "quadrilateral" that has the stated sides, just add the sides together.
40 cm (10cm x 4 sides = 40cm)
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
40cm (4 x 10 = 40)
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the average lenght of a pen can be about 10cm
A square with a side length of 10 cm has an area of 100 cm2
Area of square = (length of side)2 = (10cm)2 = 10*10 cm2 = 100 cm2
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
The perimeter of 100 square in cm is 40cm. Each side is 10cm, you get 40 when you add the four sides.
Area of small square = 1cm * 1cm = 1 cm2 Area of larger square = 10cm * 10cm = 100 cm2 Number of small squares in larger square = 100/1 = 100.