50 ft. tall you can use a proportion.
10/25=20/x
10x/10=500/10
x=50
Improved Answer:
Let the height be x:
x/25 = 24/10
Multiply both sides by 25:
x = 600/10
Height of tower = 60 feet
This problem can also be solved through trigonometry because the tangent ratio works out as 67.38013505 degrees.
A 1 foot shadow I think.
It works out as 12 feet and 4 inches in height
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
the answer is 25.
tan(36) = H/58 where H is the height of the tower. So H = 58*tan(36) = 42 feet.
2
A 1 foot shadow I think.
It is 90 feet in height
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
It works out as 12 feet and 4 inches in height
It depends on the time of day because the angle of the sun will determine the shadow length
Ratio of object to its shadow is the same. So if T is the height of the tree, then T/21 = 4/6 So T = 21*4/6 = 84/6 = 14 feet
The ratio of the height of the object to its shadow are the same for both objects. So, if H is the height of the tower, then H/500 = 40/36 therefore H = 500*40/36 = 555.55... feet.
Height of building/105 = 6/14 Multiply both sides by 105: Height = 630/14 Height = 45 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2