0

# Adjoint operator of a complex number?

Updated: 4/28/2022

Wiki User

14y ago

Adjoint operator of a complex number?

Wiki User

14y ago

Earn +20 pts
Q: Adjoint operator of a complex number?
Submit
Still have questions?
Related questions

### Is momentum hamiltonian operator is hermitian operator?

The hamiltonian operator is the observable corresponding to the total energy of the system. As with all observables it is given by a hermitian or self adjoint operator. This is true whether the hamiltonian is limited to momentum or contains potential.

### Determinant of adjoint a is given find determinant of a?

relationship between determinant and adjoint

### How can you create a new operator through operator overloading?

You cannot create a new operator through operator overloading. You can only redefine an existing operator, with certain limitations. As an example, for a class of complex numbers, having a real and an imaginary part, you might want an addition operator. This is the skeleton of code to do that. I only show the operator, not any constructors or other operators or methods, etc.class complex {private:double real, imaginary;public:complex operator+ (complex operand) {complex temp;temp.real = this.real + operand.real;temp.imaginary = this.imaginary + operand.imaginary;return temp;}};The above answer is for C++. Since this question is also categorized in Java Programming it's important to note that operator overloading is not currently possible in Java.

### What is an adjoint matrix?

The classical adjoint of a square matrix A the transpose of the matrix who (i, j) entry is the a i j cofactor.

### Write a program to write the sum of two complex number using friend function and overloading constractor?

#include&lt;iostream.h&gt; #include&lt;conio.h&gt; class complex { int r; int i; public: complex() { } complex(int a,int b) { r=a;i=b; } friend complex operator+(complex,complex); friend show(complex); complex operator+(complex c1,complex c2) { complex c3; c3.r=c1.r+c2.r; c3.i=c1.i+c2.i; return(c3); } show(complex c) { cout&lt;&lt;c.r&lt;&lt;"i+"&lt;&lt;c.i&lt;&lt;endl; } void main() { complex a,b,c; clrscr(); a.complex(3,6); b.complex(4,7); c=a+b; show(a); show(b); show(c); getch() }

### What is the operator number in the UK?

The main number for reaching a telephone operator in the UK is 100.

### What is the complex conjugate complex number 8 6i?

Since you didn't show an operator, we'll use: 1. 8-6i 2. 8+6i 3. 8 times 6i = 48i The complex conjugates are: 1. 8+6i 2. 8-6i 3. -48i

### What number can you dial to get operator?

The number of a operator will be 0 or 411.

### C program to multiply two complex no?

/*C++ program to multiply two complex numbers using * operator overloading*/ #include&lt;iostream.h&gt; #include&lt;conio.h&gt; class complex { float x,y; public: complex() {} complex(float real,float img) { x=real; y=img; } complex operator*(complex); void display() { cout&lt;&lt;x&lt;&lt;" + "&lt;&lt;y&lt;&lt;"i"&lt;&lt;endl; } }; complex complex::operator*(complex e) { complex temp; temp.x=x*e.x+y*e.y*(-1); temp.y=x*e.y+y*e.x; return(temp); } void main() { clrscr(); complex c1(5,3),c2(3,2),c3=c1*c2; c1.display(); c2.display(); cout&lt;&lt;"Multiplication"&lt;&lt;endl; c3.display(); getch(); } OUTPUT: 5 + 3i 3 + 2i Multiplication 9 + 19i

### What does of size of operator do?

The sizeof() operator returns the number of bytes allocated to the operand.

### What mobile operator in England has the number 447-879-xxxxxx?

The United Kingdom operator allocated this number is Vodafone Ltd