No. It is an imaginary (or complex) number.
The imaginary part of the complex number
–5 + 3i is
No. The sum of an irrational number and any other [real] number is irrational.
A negative irrational number can be thought of as an irrational number multiplied by -1, or an irrational number with a minus sign in front of it.
- 2 - 3i
If an irrational number is added to, (or multiplied by) a rational number, the result will always be an irrational number.
That simply isn't true. The sum of two irrational numbers CAN BE rational, but it can also be irrational. As an example, the square root of 2 plus the square root of 2 is irrational.
rational number means 3/5 and ....irrational number means imaginary part will be added eg:3i/5
The "i" in 3i means the number is imaginary.
Neither. All irrational numbers are real numbers.Using the real number system you can't take the square root of a negative number, but if you're dealing with imaginary numbers then the square root of negative 3 is the square root of 3i
3i where i is the square root of negative one.3i x 3i = -9
The conjugate is 7 - 3i is 7 + 3i.
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
[7 - 3i] To find the conjugate: the sign of the real part stays the same, and the sign of the imaginary part is reversed. So the conjugate of [7 + 3i] is [7 - 3i]
An irrational number.
The conjugate of (84-3i) is (84+3i). This gives you a real number when multiplied.
No. The sum of an irrational number and any other [real] number is irrational.
The sum of a rational and irrational number must be an irrational number.
To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.