Start print "the sum of all even numbers is infinite" end
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;
1.start 2.n=1,s=0 3 compute s=s+n 4 compute n=n+1 5 check n<=10 go to step3 else go to step 7 6 display s 7 stop
even numbers
98,376
Start print "the sum of all even numbers is infinite" end
No, all even numbers greater than two are composite.
jgfujtf
yes
Euclid's algorithm is a time-tested method for finding the greatest common divisor (GCD) of two numbers. It's based on the principle that the greatest common divisor of two numbers also divides their difference. This algorithm is efficient and works well for large numbers, making it a practical choice in numerous applications. The algorithm operates in a recursive or iterative manner, continually reducing the problem size until it reaches a base case. Hereโs how Euclid's algorithm works: print (gcd (a, b) ) # Output: 3ere >a>b , subtract b from a. Replace a with (aโb). Repeat this process until a and b become equal, at which point, a (or b) is the GCD of the original numbers. A more efficient version of Euclidโs algorithm, known as the Division-based Euclidean Algorithm, operates as follows: Given two numbers a and b, where >a> b, find the remainder of a divided by b, denoted as r. Replace a with b and b with r. Repeat this process until b becomes zero. The non-zero remainder, a, is the GCD of the original numbers. In this example, even though a and b are large numbers, the algorithm quickly computes the GCD. The division-based version of Euclidโs algorithm is more efficient than the subtraction-based version, especially for large numbers, as it reduces the problem size more rapidly. Euclid's algorithm is a fundamental algorithm in number theory, with applications in various fields including cryptography, computer science, and engineering. Its efficiency and simplicity make it a powerful tool for computing the GCD, even for large numbers.
24680 using only even numbers or 12346 which is an even number
sum = 0 for(n = 0; n <= 10; n += 2) sum += n;
9338
== == == == == == == == == ==
#include using std::cout;using std::endl;int main(){int arr[] = {2, 45, 34, 56, 56};//you define here your array of even and odd numbersint arrSize = sizeof arr/sizeof arr[0];int numEven = 0;int numOdd = 0;for (int i = 0; i < (arrSize - 1); i++){if (arr[i] % 2 == 0){numEven++;}else{numOdd++;}}cout
88,888
1,476 is.