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How do you solve this An arrow is fired into the air with an initial velocity of 160 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function?
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
How do you calculate height based on velocity and time?
I assume you refer to the formula distance = velocity x time. If an object moves upward, the distance would become the height.
How do geometric sequences apply to a bouncing ball?
The ball does not return to its initial height after bouncing. So the height it reaches after the first bounce will be a fraction of the initial height, etc. This is a geometric sequence with common ratio 5/8.
How do you find height if only velocity is given?
In that case, you don't have enough information.
What is the vertical motion formula?
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
How does the initial velocity change with he point of released of inclined plane?
The initial velocity of an object released from an inclined plane depends on the height from which it is released. The higher the release point, the greater the initial velocity of the object due to the larger potential energy it possesses. This initial velocity will determine the object's motion once it leaves the inclined plane.
An object projected up with initial velocity v attains a height h Another object projected up with initial velocity 2v will attain what height?
The height attained by an object projected up is directly proportional to the square of its initial velocity. So, if an object with initial velocity v attains a height h, then an object with initial velocity 2v will attain a height of 4 times h.
What is the equation to calculate the maximum height of an object given an initial velocity and initial launch height?
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
What is A football kicked off at an angle 20 from the ground reaches a maximum height of 4.7 m What is the initial velocity of the kick?
To find the initial velocity of the kick, you can use the equation for projectile motion. The maximum height reached by the football is related to the initial vertical velocity component. By using trigonometric functions, you can determine the initial vertical velocity component and then calculate the initial velocity of the kick.
How can one determine the maximum height reached by an object launched with a given initial velocity?
To determine the maximum height reached by an object launched with a given initial velocity, you can use the formula for projectile motion. The maximum height is reached when the vertical velocity of the object becomes zero. This can be calculated using the equation: Maximum height (initial velocity squared) / (2 acceleration due to gravity) By plugging in the values of the initial velocity and the acceleration due to gravity (which is approximately 9.81 m/s2 on Earth), you can find the maximum height reached by the object.
How do initial velocity affect range and height of a projectile?
Increasing the initial velocity of a projectile will increase both its range and height. Higher initial velocity means the projectile will travel further before hitting the ground, resulting in greater range. Additionally, the increased speed helps the projectile reach a higher peak height before it begins to descend back down.
What relationship exists between the initial velocity and the maximum height reached by an object thrown upward?
Ignoring air resistance, I get this formula:Maximum height of a vertically-launched object = 1.5 square of initial speed/GI could be wrong. In that case, the unused portion of my fee will be cheerfully refunded.
How does the height from which an object was dropped affect its average velocity?
The height from which an object is dropped does not affect its average velocity. Average velocity depends on the overall displacement and time taken to achieve that displacement, regardless of the initial height of the object.
The velocity of a body thrown vertically upward is reduced into half in one secondwhat is the maximum height attained by it?
The maximum height attained by the body can be calculated using the formula: height = (initial velocity)^2 / (2 * acceleration due to gravity). Since the velocity is reduced to half in one second, we can calculate the initial velocity using the fact that the acceleration due to gravity is -9.81 m/s^2. Then, we can plug this initial velocity into the formula to find the maximum height reached.
How to find the height of the projectile launch if the angle velocity and the distance are given?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
. ok v velocity a acceleration but what about you?
if by 'you', you mean 'u' then u is the initial velocity v is the final velocity. you need to know the initial velocity in trajectory question (motion of an object through the air) to find height, acceleration, time etc.
How can one determine the maximum height reached by a projectile?
To determine the maximum height reached by a projectile, you can use the formula: maximum height (initial vertical velocity)2 / (2 acceleration due to gravity). This formula calculates the height based on the initial vertical velocity of the projectile and the acceleration due to gravity.
