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If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
I assume you refer to the formula distance = velocity x time. If an object moves upward, the distance would become the height.
The ball does not return to its initial height after bouncing. So the height it reaches after the first bounce will be a fraction of the initial height, etc. This is a geometric sequence with common ratio 5/8.
In that case, you don't have enough information.
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
4h
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
initial velocity of the kick = 28.06 m/s
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
if by 'you', you mean 'u' then u is the initial velocity v is the final velocity. you need to know the initial velocity in trajectory question (motion of an object through the air) to find height, acceleration, time etc.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
To answer this question one would need to know the rock's initial height and velocity.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
That depends on a number of different variables and therefore it cannot be concluded here. It depends on the mass of the object being swung as well as the initial conditions of this object such as the height it is released or the initial velocity by which it was flung.
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.