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How do you solve this An arrow is fired into the air with an initial velocity of 160 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function?
Marcbeaubrun
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agolet v = initial velocity and height = h then
h = vt -16t^2
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