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RΒ² plus r-20 equals 0?
r2 + r - 20 = 0(r + 5)(r - 4) = 0r + 5 = 0 or r - 4 = 0r = -5 or r = 4
Pqr when p equals 2 q equals 4 andd r equals 5?
PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
How do you find the y intercept when you are given the coordinates 5 and 4?
Having one given point is not enough. A y-intercept is described as the point of intersection of a function or relation or line and the ordinate axis (or y-axis).Suppose a function intersects the y-axis at (0, 6), then 6 is the value of the y-intercept. Or if the line that passes through (5, 4) is parallel to x-axis, then y-intercept is 4; if it passes through the origin, then y-intercept is 0; if it is perpendicular to x-axis (or parallel to y-axis) there is not an y-intercept.
If p is 50 percent of q and r is 40 percent of q what percent of r is p?
p = 50q/100 = 1/2 q r = 40q/100 = 2/5 q p = (1/2)/(2/5) = (1/2)(5/2) = 5/4 r or 1 1/4 r Thus, p is 125% of r.
What is 49 divided by 5 with the remainder?
9.8
RΒ² plus r-20 equals 0?
r2 + r - 20 = 0(r + 5)(r - 4) = 0r + 5 = 0 or r - 4 = 0r = -5 or r = 4
Is 5 r 1 4 r 5 the same?
No, they are not.
What is the distance of point -3 4 from x axis?
5 units
What is the Moment of inertia of a cone rotating around its axis of rotational symmetry?
The moment of inertia of a cone about its central axis, start with the standard Intertia equation I = integral r^2 dm dm = rho dV (rho is density) (dV is basically volume) dV = r dr dtheta dx not going to prove that here but you will see in the integral that this does indeed form the volume. integral will be refered to as int from here on. This now forms the triple integral I = rho int(0 to H) int(0 to 2pi) int(0 to r) r^3 dr dtheta dx solving the integral leaves I = rho int(0 to H) int(0-2pi) 1/4 r^4 dtheta dx solving the second integral leaves I = rho int(0 to H) 1/2 pi r^4 dx ok so now you have to sub in the equation for r (the radius) of the cone r = (R/H)x this is the radius at the base divided by the height of the cone multiplied by the distance along the x axis. this equation gives you r at any point this gives you I = rho int(0 to H) 1/2 pi [(R/H)x]^4 dx time to do some housekeeping and take all the constants outside the integral I = (rho pi R^4) / (2 H^4) int(0 to H) x^4 dx this can now be solved and simplified to I = (rho pi R^4 H) / 10 At this stage your solution is complete, however you can tidy up the equation by taking out the mass term. m = (rho pi H R^2) / 3 split the Inertia term up to serperate out the mass term I = [(rho pi H R^2) / 3]*[ (3R^2)/10 ] this is now the complete solution in terms of mass I = (3mR^2)/10 I hope this manages to help some poor unfortunate student who gets set this question.
2/5(r-2)=3/20(r-4)?
2/5(πβ2)=3/20(rβ4) 2(πβ2)/5=3/20(πβ4) 2πβ4/5=3/20(πβ4) 2πβ4/5=3(πβ4)/20 π=45
What is the graph of r 4sinΞΈ?
The graph is a circle, with a diameter of 4, centered at the point (2, 0) on the x-axis.
This ellipse has a horizontal axis of length 10 and a vertical axis of length 4 What is its equation?
By taking a coordinate system with origin at the center of the ellipse, and x-axis along the major axis, and y-axis along the minor axis, then the ellipse intercepts the x-axis at -5 and 5, and the y-axis at -2 and 2. So that the equation of the ellipse x2/a2 + y2/b2 = 1 becomes x2/52 + y2/22 = 1 or x2/25 + y2/4 = 1.
How do you reflect over x axis?
You change the value of y to -y. ex: (4,5) reflected over the x-axis is (4,-5)
What is the slope of the line that passes through the points 3 4 and 5 4?
Points: (3, 4) and (5, 4) Slope: (4-4)/(3-5) = 0 There is no slope and it is a straight line parallel to the x axis
Where is the number 4 and 5 on the keyboard of a computer?
They are in the row just above the letters. The 4 is above the e and r. The 5 is above the r and t.
What is the answer to y equals 4x-5 in a mapping diagram?
9
Pqr when p equals 2 q equals 4 andd r equals 5?
PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
