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Yes.

The factors of 100 are 2,2,5 and 5 i.e. 100 = 10 x 10 and 10 = 2 x 5 so 100 = 2 x 2 x 5 x 5

81 is the square of 9 (i.e. 81 = 9 x 9)

9 is also the square of 3 (i.e. 9 = 3 x 3 )

So the factors of 81 are 9 x 9 = 3 x 3 x 3 x 3

Now it is clear that the two original numbers have no common factors and therefore they are "relatively prime" though neither alone is a Prime number as they are both squares.

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Q: Are 81 and 100 relatively prime?
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