Two letters = 26*26 = 676 possibilities
4 digits = 104 possibilities (if numbers such as 0000 are permitted).
All in all, 6.76*106 possibilities. That should keep Oxnard University going for a few years.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
One way to work this out is to imagine that you have a bag containing all 26 letters of the alphabet.Take one letter from the bag. It could be any one of the 26, so there are 26 possibilities for your first letter.Take another letter from the bag. This time there are only 25 letters in the bag (you've already taken one out, remember!). So you have 25 possibilities for the second letter.So far there are 26 x 25 (= 650) possibilities for your first two letters. (AB, BA, AC, CA, AD, DA, etc)Now take your third letter from the bag. But remember, there are now only 24 letters remaining.So, for 'from 26 chose 3', altogether you have 26 x 25 x 24 possibilities, which comes to 15,600 different combinations of three different letters.
There are likely to be hundreds - if not thousands of possibilities. It depends how many letters you're allowed to use. For some examples - see the related question, which has already been answered.
3 decimal digits without repeats can form (10 x 9 x 8) = 720 distinct displays.For each of these . . .3 letters without repeats can form (26 x 25 x 24) = 15,600 distinct displays.Combine them on one plate, and there are (720) x (15,600) = 11,232,000 distinct displays available.
I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination. There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc. All in all, therefore, 17,576,000 permutations. However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
each of the four numbers have 10 possibilities, and each of the three letters have 26 possibilities. so the total possible ways u can arrange them are 10x10x10x10x26x26x26 this totals up to 175,760,000 different license plate numbers
There are 26 possibilities for the first two blanks and 10 possibilities each for the last 4 blanks. Then we can derive this equation: 26*26*10*10*10*10= 6,760,000 possibilities.
Consists of four numbers followed by two letters. It depends on where in Utrecht. In the city it's something between 3511 and 3585.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
Dragnets.
There are up to 3 numbers and up to 5 letters in a UK postcode. One or two letters, followed by one or two digits OR one digit and a letter, followed by a space, followed by one digit, followed by two letters.
There are 36504 different possibilities.
lmnopqrstuvwxyz
No.
How many license plates can be made using either two uppercase English letters followed by four digits or two digits followed by four uppercase English letters?
SCIENCE