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I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination.

There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc.

All in all, therefore, 17,576,000 permutations.

However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.

Q: How many license plate combinations with three letters and two digits?

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There are 676,000 ways to make the license plates.

If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.

765

3 decimal digits without repeats can form (10 x 9 x 8) = 720 distinct displays.For each of these . . .3 letters without repeats can form (26 x 25 x 24) = 15,600 distinct displays.Combine them on one plate, and there are (720) x (15,600) = 11,232,000 distinct displays available.

If the identifying information on each license plate consists of (letter-1)(letter-2)(digit-1)(digit-2)(digit-3)(digit-4), and repetition is allowed: letter-1 has 26 choices, and for each one ... letter-2 has 26 choices, and for each one ... digit-1 has 10 choices, and for each one ... digit-2 has 10 choices, and for each one ... digit-3 has 10 choices, and for each one ... digit-4 has 10 choices. Total number of choices = 262 x 104 = ( 26 x 26 x 10 x 10 x 10 x 10 ) = 676 x 10,000 = 6,760,000

Related questions

There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.

In most states, the number itself tells those who need to know what kind of license it is. In California, most cars and trucks have a digit, three letters and three more digits. A commercial truck plate has a letter followed by six digits, and there are other combinations for big trucks, trailers, and other categories.

2600

There are 676,000 ways to make the license plates.

26x26x26x10x10x10 = 17,576,000

If I understand correctly the first number has to be '1', the next three digits have to be letters, and the last digit can't be '0', so there are1x26x26x26x10x10x9 = 15,818,400 possible Californian licence plate combinations.

If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.

Independent events, so P(both)=(5/26)(4/10)=0.07692307692. The 4/10 comes from the fact that 0, 3, 6, and 9 are the 4 digits that are multiples of 3.

In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.

100,000,000,000,000,000,000,000,000

Presumably... 24 X 24 X 24 X 10 X 10 X10. If you don't mind the I (eye) being confused with the 1 (one) and etc. You mean permentations right, where ABA is different from BAA? At least that is what I answered.

This depends on if you want repeats or not (or the state you are in) with repeats it is: 26x26x26x10x10= 1,757,600 without repeats it is: 26x25x24x10x9=1,560,000