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I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination.
There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc.
All in all, therefore, 17,576,000 permutations.
However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
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How many different ways can a license plate be made containing two letters and three digits with repetition of the numbers and letters not allowed?
There are 676,000 ways to make the license plates.
If a license plate consists of two letters followed by four digits how many different plates are possible?
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
A license plate has a three-digit number printed on it The product of the digits is 210 their sum is 18 and the numbers appear in descending order from left to right what is the license plate number?
765
How many license plates with 3 decimal digits followed by 3 letters can you build if you are not allowed to repeat digits and you are not allowed to repeat letters?
3 decimal digits without repeats can form (10 x 9 x 8) = 720 distinct displays.For each of these . . .3 letters without repeats can form (26 x 25 x 24) = 15,600 distinct displays.Combine them on one plate, and there are (720) x (15,600) = 11,232,000 distinct displays available.
If automobile license plates consist of two letters followed by four digits how many different possible license plates are possible if letters and numbers can be repeated?
If the identifying information on each license plate consists of (letter-1)(letter-2)(digit-1)(digit-2)(digit-3)(digit-4), and repetition is allowed: letter-1 has 26 choices, and for each one ... letter-2 has 26 choices, and for each one ... digit-1 has 10 choices, and for each one ... digit-2 has 10 choices, and for each one ... digit-3 has 10 choices, and for each one ... digit-4 has 10 choices. Total number of choices = 262 x 104 = ( 26 x 26 x 10 x 10 x 10 x 10 ) = 676 x 10,000 = 6,760,000
