I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination.
There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc.
All in all, therefore, 17,576,000 permutations.
However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
There are 676,000 ways to make the license plates.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
765
3 decimal digits without repeats can form (10 x 9 x 8) = 720 distinct displays.For each of these . . .3 letters without repeats can form (26 x 25 x 24) = 15,600 distinct displays.Combine them on one plate, and there are (720) x (15,600) = 11,232,000 distinct displays available.
If the identifying information on each license plate consists of (letter-1)(letter-2)(digit-1)(digit-2)(digit-3)(digit-4), and repetition is allowed: letter-1 has 26 choices, and for each one ... letter-2 has 26 choices, and for each one ... digit-1 has 10 choices, and for each one ... digit-2 has 10 choices, and for each one ... digit-3 has 10 choices, and for each one ... digit-4 has 10 choices. Total number of choices = 262 x 104 = ( 26 x 26 x 10 x 10 x 10 x 10 ) = 676 x 10,000 = 6,760,000
To calculate the number of license plate combinations using three letters and four numbers, we consider the possibilities for each part separately. There are 26 letters in the English alphabet, so for three letters, there are (26^3) combinations. For the four numbers, using digits 0-9, there are (10^4) combinations. Therefore, the total number of combinations is (26^3 \times 10^4), which equals 17,576,000 combinations.
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
To calculate the number of license plate combinations between AAA-000 and ZZZ-999, we consider that there are 26 letters (A-Z) for each of the three letter positions and 10 digits (0-9) for each of the three digit positions. This gives us (26^3 \times 10^3 = 17,576 \times 1,000 = 17,576,000) possible combinations. Therefore, there are 17,576,000 unique license plate combinations in this range.
In most states, the number itself tells those who need to know what kind of license it is. In California, most cars and trucks have a digit, three letters and three more digits. A commercial truck plate has a letter followed by six digits, and there are other combinations for big trucks, trailers, and other categories.
2600
There are 676,000 ways to make the license plates.
To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.
If I understand correctly the first number has to be '1', the next three digits have to be letters, and the last digit can't be '0', so there are1x26x26x26x10x10x9 = 15,818,400 possible Californian licence plate combinations.
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
Independent events, so P(both)=(5/26)(4/10)=0.07692307692. The 4/10 comes from the fact that 0, 3, 6, and 9 are the 4 digits that are multiples of 3.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
The "AB" on a 1937 California license plate indicates the series or type of the plate issued during that year. California license plates from that era used a combination of letters and numbers to designate different registrants, with the letters often denoting a specific sequence or category. Each year, the state released new registrations, and the letter combinations helped differentiate vehicles registered in different years.