One way to work this out is to imagine that you have a bag containing all 26 letters of the alphabet.
Take one letter from the bag. It could be any one of the 26, so there are 26 possibilities for your first letter.
Take another letter from the bag. This time there are only 25 letters in the bag (you've already taken one out, remember!). So you have 25 possibilities for the second letter.
So far there are 26 x 25 (= 650) possibilities for your first two letters. (AB, BA, AC, CA, AD, DA, etc)
Now take your third letter from the bag. But remember, there are now only 24 letters remaining.
So, for 'from 26 chose 3', altogether you have 26 x 25 x 24 possibilities, which comes to 15,600 different combinations of three different letters.
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3,124,550 possible combinations
676,000 but I don’t know why
With a Latin alphabet of 26 letters and the 10 digits 0...9, and allowing for repeats, you get: 36^4 = 36 × 36 × 36 × 36 = 1,679,616 combinations. If you were to include both lower and upper case characters, the number of possible combinations goes up (due to 26 lower case letters + 26 upper case letters + 10 digits = 62 characters to choose from): 62^4 = 14,776,336.
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.