An infinite number of multiples of 31 can be divided by 31.
31
any number divided by 1 it is itself 1 divided by 2 = 1 it is veryy easy so pls like
Any number can be divided by two (or any non-zero number for that mater).
The odd number between 26 and 36 is 29. An odd number is any integer that cannot be divided evenly by 2, leaving a remainder of 1. In this case, 29 is the only odd number within the range specified.
An infinite number of multiples of 31 can be divided by 31.
31 is a prime number so it can only be divided by 1 and 31.
Only by its factors which are: 1, 3, 31 and 93
X/31 where X is the number
Yes, 31 can only divided by 1 and 31. So it is a prime number
To work it out for yourself, you need to understand that a prime number is a number than can only be divided by 1 and itself. 18 can be divided by 2 39 can be divided by 3 42 can be divided by 2 which leaves 31 which can only be divided by 1 and 31.
31
Any number can be divided by any number but not come out as a whole number,
Any number is divided by 1 is that number.
any number divided by 1 it is itself 1 divided by 2 = 1 it is veryy easy so pls like
23. If the remainder when a number n is divided by m is r, then it is written as n ≡ r MOD m (read as "n is equivalent to r modulo m") and n = mk + r for some integer k. if n ≡ 643 MOD 837, then n = 837k + 643 (for some k) When n is divided by 31: n ÷ 31 = (837k + 643) ÷ 31 = 837k ÷ 31 + 643 ÷ 31 = 27k + 20 + 23/31 Multiplying both sides by 31: → n = 31 x (27k + 20) + 31 x 23/31 = 31m + 23 (where m = 27k + 20) → n ≡ 23 MOD 31 Thus the remainder when the same number is divided by 31 is 23.
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