31 is prime
31
Half of a number is the result of dividing the number by 2. In this case, half of 31 is 31 divided by 2, which equals 15.5.
When a number is divided by 32, the remainder can range from 0 to 31, as the remainder can never be greater than the divisor. Therefore, the greatest value the remainder may have is 31.
222222222222
31 is a prime number so it can only be divided by 1 and 31.
X/31 where X is the number
31 is prime
Yes, 31 can only divided by 1 and 31. So it is a prime number
To work it out for yourself, you need to understand that a prime number is a number than can only be divided by 1 and itself. 18 can be divided by 2 39 can be divided by 3 42 can be divided by 2 which leaves 31 which can only be divided by 1 and 31.
31
23. If the remainder when a number n is divided by m is r, then it is written as n ≡ r MOD m (read as "n is equivalent to r modulo m") and n = mk + r for some integer k. if n ≡ 643 MOD 837, then n = 837k + 643 (for some k) When n is divided by 31: n ÷ 31 = (837k + 643) ÷ 31 = 837k ÷ 31 + 643 ÷ 31 = 27k + 20 + 23/31 Multiplying both sides by 31: → n = 31 x (27k + 20) + 31 x 23/31 = 31m + 23 (where m = 27k + 20) → n ≡ 23 MOD 31 Thus the remainder when the same number is divided by 31 is 23.
The number 31 can go into the number 155 a total of 5 times.
0.1613
16 and 31
31
The only prime number among the options given is 31. A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. In this case, 31 cannot be divided evenly by any other number except for 1 and 31, making it a prime number.