If you are given a plane, you can always find and number of points that are not in that plane but, given anythree points there is always at least one plane that goes through all three.
An angle separates a plane to 3 sets: 1) Points between the 2 rays 2) Points on one of the rays 3) Points outside of the 2 rays
They are coplanar. ANY 2 lines would be coplanar, however a third line can be outside of the plane. just like 3 points will designate a plane and a triangle
Any 4 points can lie in a plane, 3 points determine a plane and just take the 4th to be say the origin.
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No, A plane can be drawn through any 3 points. If the 3 points are collinear then they make a line and a plane can contain a line. If the points are noncollinear then they can be used to form the corners of a triangle; all points of a triangle are in the same plane.
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An angle separates a plane to 3 sets: 1) Points between the 2 rays 2) Points on one of the rays 3) Points outside of the 2 rays
A cube has 8 non-coplanar points at the vertices and has 6 faces. This is only a partial answer...3 points determine a plane so there will be many more than 6. Your answer is going to be found by the formula n!/(n-r)! where n=8 and r=3. That gives: 40320/120 = 336
A plane has an infinite number of points. It takes 3 points to fix a plane i.e. you need 3 points to identify one unique plane.
The three parts are:the interior of the circle, the points on the circle (points on its circumference) the outside of the circle.
Every plane has 3 or more. There is a projective (or affine) plane with only 3 points.
Any 3 points determine a plane.
They are coplanar. ANY 2 lines would be coplanar, however a third line can be outside of the plane. just like 3 points will designate a plane and a triangle
No, 2 points define a line, 3 points define a plane.
Any 4 points can lie in a plane, 3 points determine a plane and just take the 4th to be say the origin.
no 2 points form a line, 3 points form a plane