Yes, the common ratio in a geometric progression can be 1. In a geometric progression, each term is obtained by multiplying the previous term by a constant factor, known as the common ratio. When the common ratio is 1, each term is equal to the previous term, resulting in a sequence of repeated values. This is known as a constant or degenerate geometric progression.
Chat with our AI personalities
if a number is multiplied by 1, then it does not change, it is Still the same number. A ratio of 1 is impossible . The ratio between two quantities must always be greater than 1 otherwise there is no difference between them.
For an Arithmetic Progression, Sum = 15[a + 7d].{a = first term and d = common difference} For a Geometric Progression, Sum = a[1-r^15]/(r-1).{r = common ratio }.
It's a geometric progression with the initial term 1/2 and common ratio 1/2. The infinite sum of the series is 1.
The absolute value of the common ratio is less than 1.
Divide any term in the sequence by the previous term. That is the common ratio of a geometric series. If the series is defined in the form of a recurrence relationship, it is even simpler. For a geometric series with common ratio r, the recurrence relation is Un+1 = r*Un for n = 1, 2, 3, ...
A geometric series represents the partial sums of a geometric sequence. The nth term in a geometric series with first term a and common ratio r is:T(n) = a(1 - r^n)/(1 - r)