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Divide any term in the sequence by the previous term. That is the common ratio of a geometric series.
If the series is defined in the form of a recurrence relationship, it is even simpler.
For a geometric series with common ratio r, the recurrence relation is
Un+1 = r*Un for n = 1, 2, 3, ...
104, -52, 26, -13,
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What is the 7th term in the geometric sequence whose first term is 5 and the common ratio is -2?
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
The sum to three terms of geometric series is 9 and its sum to infinity is 8. What could you deduce about the common ratio. Why. Find the first term and common ratio?
The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.
How do you find the 99th nth term in a geometric sequence?
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
A geometric series has first term 4 and its sum to infinity is 5 Find the common ratio?
1/8
find the next two terms in geometric sequence 2,6,18,54,162,486,1458?
It is 4374
What is the 7th term in the geometric sequence whose first term is 5 and the common ratio is -2?
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
What is the common ratio of the geometric sequence 625 125 25 5 1?
It is 0.2
Find the common ratio what geometric sequence 3.512 12.292 43.022 150.577 527.020?
The ratio can be found by dividing any (except the first) number by the one before it.
The sum to three terms of geometric series is 9 and its sum to infinity is 8. What could you deduce about the common ratio. Why. Find the first term and common ratio?
The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.
How do you find the 99th nth term in a geometric sequence?
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
A geometric series has first term 4 and its sum to infinity is 5 Find the common ratio?
1/8
How do you find the given term in a geometric sequence?
nth term Tn = arn-1 a = first term r = common factor
Find the common ratio of the following geometric sequence 2.512 11.304 50.868 228.906 1030.077?
Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:
Find the 10th term of the geometric sequence 10,-20,40…?
-5,120
find the next two terms in geometric sequence 2,6,18,54,162,486,1458?
It is 4374
What will be the first term and the common ratio of geometric progression whose 6th and 9th terms are 160 and 1280 respectively?
To find the first term and common ratio of a geometric progression, we can use the formula for the nth term of a geometric sequence: (a_n = a_1 \times r^{(n-1)}). Given that the 6th term is 160 and the 9th term is 1280, we can set up two equations using these values. From the 6th term, we get (a_1 \times r^5 = 160), and from the 9th term, we get (a_1 \times r^8 = 1280). By dividing the two equations, we can eliminate (a_1) and solve for the common ratio (r).
How do you find the geometric sequence?
a = -4 r = -3
