Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
1/8
It is 4374
Find the 7th term of the geometric sequence whose common ratio is 1/2 and whose first turn is 5
It is 0.2
The ratio can be found by dividing any (except the first) number by the one before it.
The geometric sequence with three terms with a sum of nine and the sum to infinity of 8 is -9,-18, and 36. The first term is -9 and the common ratio is -2.
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
1/8
nth term Tn = arn-1 a = first term r = common factor
Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:
-5,120
It is 4374
To find the first term and common ratio of a geometric progression, we can use the formula for the nth term of a geometric sequence: (a_n = a_1 \times r^{(n-1)}). Given that the 6th term is 160 and the 9th term is 1280, we can set up two equations using these values. From the 6th term, we get (a_1 \times r^5 = 160), and from the 9th term, we get (a_1 \times r^8 = 1280). By dividing the two equations, we can eliminate (a_1) and solve for the common ratio (r).
a = -4 r = -3