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How can graphs be used to estimate the solution for a system of linear equations?

Graphs can be used in the following way to estimate the solution of a system of liner equations. After you graph however many equations you have, the point of intersection will be your solution. However, reading the exact solution on a graph may be tricky, so that's why other methods (substitution and elimination) are preferred.


What is the exact solution to cosx equals x?

There is no "exact" solution. This type of equation falls into the category of transcendental equations, which generally don't have exact solution except in special cases. The approximate solution, however, is roughly 0.739085


What is the purpose and functionality of the MATLAB backslash command in solving linear systems of equations?

The MATLAB backslash command () is used to efficiently solve linear systems of equations by performing matrix division. It calculates the solution to the system of equations by finding the least squares solution or the exact solution depending on the properties of the matrix. This command is particularly useful for solving large systems of linear equations in a fast and accurate manner.


How many solutions does the nonlinear system of equations graphed when the graph open up and down?

A system of equations means that there are more than one equations. The answer depends on the exact function(s).


What is the answer to The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approximately equal?

To find the x-value where the two equations are approximately equal between -2 and -1.5, you would typically evaluate the two equations at various points in that range. By checking values or using methods such as graphing or numerical approximation (like the bisection method), you can determine the specific x-value where the equations intersect. Without specific equations provided, it's impossible to give an exact answer, but the solution lies in that interval.


What is the limitation of Schrodinger equations?

The biggest limitation by far is that an exact solution is possible for only a small number of initial conditions. For example, one can figure out the solution for permitted states of one electron around a nucleus. However, there is no exact solution for even two electrons around a nucleus.


Which of these is a reason to substitute the values back into the equations when solving a system by graphing?

you cannot determine the exact value of the point


Why is trial and error so useful in math?

There are many equations for which there is no method for obtaining an exact solution. In such circumstances, an efficient trial and error method may be the only way.


What does Karl Schwarzschild find as a solution to Einstein and general relativity equations?

Karl Schwarzschild found the first exact solution to Einstein's field equations in the context of general relativity. This solution describes the gravitational field around a spherically symmetric mass, giving rise to what is now known as the Schwarzschild metric, which describes the geometry of spacetime near a non-rotating, uncharged black hole.


How do you solve equations using square root?

The answer will depend on the exact nature of the equation.


What did Karl Schwarzschild discover?

Karl Schwarzschild discovered the first exact solution to Einstein's field equations of general relativity, now known as the Schwarzschild metric. This solution describes the gravitational field outside a spherically symmetric non-rotating mass, such as a black hole.


What is the answer to 13x-2y equals 70 and 2x-2y equals 4 using the method of substitution?

i am guessing here that this is what you mean as it involves substitution: 2x-2y = 4 therefore -2y = 4 - 2x Sub the above line into the first equation gives: 13x - 2x +4 = 70 11x = 66 x=6 then sub in x 13(6) - 2y = 70 78 - 2y = 70 y=4 Yep, this is the exact same as simultaneous equations