yes
you cannot determine the exact value of the point
The answer will depend on the exact nature of the equation.
Negative 1.047197551 etc, etc.
-1
9
Graphs can be used in the following way to estimate the solution of a system of liner equations. After you graph however many equations you have, the point of intersection will be your solution. However, reading the exact solution on a graph may be tricky, so that's why other methods (substitution and elimination) are preferred.
There is no "exact" solution. This type of equation falls into the category of transcendental equations, which generally don't have exact solution except in special cases. The approximate solution, however, is roughly 0.739085
The MATLAB backslash command () is used to efficiently solve linear systems of equations by performing matrix division. It calculates the solution to the system of equations by finding the least squares solution or the exact solution depending on the properties of the matrix. This command is particularly useful for solving large systems of linear equations in a fast and accurate manner.
A system of equations means that there are more than one equations. The answer depends on the exact function(s).
To find the x-value where the two equations are approximately equal between -2 and -1.5, you would typically evaluate the two equations at various points in that range. By checking values or using methods such as graphing or numerical approximation (like the bisection method), you can determine the specific x-value where the equations intersect. Without specific equations provided, it's impossible to give an exact answer, but the solution lies in that interval.
The biggest limitation by far is that an exact solution is possible for only a small number of initial conditions. For example, one can figure out the solution for permitted states of one electron around a nucleus. However, there is no exact solution for even two electrons around a nucleus.
you cannot determine the exact value of the point
There are many equations for which there is no method for obtaining an exact solution. In such circumstances, an efficient trial and error method may be the only way.
Karl Schwarzschild found the first exact solution to Einstein's field equations in the context of general relativity. This solution describes the gravitational field around a spherically symmetric mass, giving rise to what is now known as the Schwarzschild metric, which describes the geometry of spacetime near a non-rotating, uncharged black hole.
The answer will depend on the exact nature of the equation.
Karl Schwarzschild discovered the first exact solution to Einstein's field equations of general relativity, now known as the Schwarzschild metric. This solution describes the gravitational field outside a spherically symmetric non-rotating mass, such as a black hole.
i am guessing here that this is what you mean as it involves substitution: 2x-2y = 4 therefore -2y = 4 - 2x Sub the above line into the first equation gives: 13x - 2x +4 = 70 11x = 66 x=6 then sub in x 13(6) - 2y = 70 78 - 2y = 70 y=4 Yep, this is the exact same as simultaneous equations