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The vertex of the parabola below is at the point 4 -1 which equation be this parabola's equation?
5
The vertex of this parabola is at (4 -3). When the x-value is 5 the y-value is -6. What is the coefficient of the squared expression in the parabola's equation?
-3
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5 What is the coefficient of the squared term in the parabola's equation?
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?
2
What is the coefficient of the squared term in the parabola's equation when the vertex is at -2 -3 and the point -1 -5 is on it?
A parabola with vertex (h, k) has equation of the form: y = a(x - h)² + k → vertex (k, h) = (-2, -3), and a point on it is (-1, -5) → -5 = a(-1 - -2)² + -3 → -5 = a(1)² - 3 → -5 = a - 3 → a = -2 → The coefficient of the x² term is -2.
The vertex of the parabola below is at the point 4 -1 which equation be this parabola's equation?
5
What are the coordinates of the vertex of the parabola described by the equation below?
The coordinates will be at the point of the turn the parabola which is its vertex.
The vertex of this parabola is at 4 -3 When the x-value is 5 the y-value is -6 What is the coefficient of the squared expression in the parabola's equation?
-3
The vertex of this parabola is at (2, -4) When the y-value is -3, the x-value is -3 What is the coefficient of the squared term in the parabola's equation?
-5
The vertex of this parabola is at (4 -3). When the x-value is 5 the y-value is -6. What is the coefficient of the squared expression in the parabola's equation?
-3
The vertex of this parabola is at 5 -4 Which of the equations below could be its equation?
9
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1 What is the coefficient of the squared expression in the parabola's equation?
The vertex of this parabola is at 5 5 When the x-value is 6 the y-value is -1. The coefficient of the squared expression in the parabola's equation is -6.
What is the y coordinate of the vertex of the parabola that is given y equals negative 2 point 5 parenthese x minus 4 parenthese end squared minus 5?
y = -5 By using calculus, the derivative of y = -2.5(x-4)2 - 5 is y' = -5(x-4). Solving the equation -5(x-4) = 0 gives x = 4 (since the slope of the parabola at the vertex is zero). Plug this back into the equation: y = -2.5(4 - 4) -5 = -5, so the y-coordinate is -5. The equation of the parabola is given in the vertex form y = a(x - h)2 + k, where (h, k) is the vertex. So the vertex is (4, -5).
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5 What is the coefficient of the squared term in the parabola's equation?
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2 What is the coefficient of the squared expression in the parabola's equation?
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
Write the equation of the parabola in vertex form vertex 4 3 point 3 5?
So you need something like this: y = a*(x - 4)² + 3. This will make the vertex be at (4,3). Then it looks like you have another point on the parabola (3,5). Plug that in and solve for a. 5 = a*(3-4)² + 3. This becomes 5 = a + 3, so a=2, then the equation is: y = 2*(x - 4)² + 3
The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?
2
