It has one nucleon
it has no neutrons
it has one proton
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If 5*(p + 6) = 25 then p is -1
Suppose the perfect number P has divisors f1, f2, ... , fk, P (where all the fs are smaller than P. Then, by the definition of a perfect number, f1 + f2 + ... + fk = P So that f1 + f2 + ... + fk + P = 2P Dividing through by P, f1/P + f2/P + ... + fk/P + P/P = 2 . . . . . . . . . . . (2) Now, since f1 is a factor of P, the f1*g1 = P where g is the cofactor and so f1/P = 1/g1. That is, f1/P is the reciprocal of one of the other factors of P. Also, the last term on the left is the reciprocal of the factor 1. And therefore, f1/P + f2/P + ... + fk/P + P/P = 2 = 1/g1 + 1/g2 + ... + 1/gk + 1/1
5 p/1 pound = 5 p/100 p = 1/20
No, it is not.Incidentally, is a number p is prime then its 2 factors are 1 and p. Their sum is p+1.If p is a perfect number then this sum must be 2p.That is, p+1 = 2p or p = 1.But 1 is not a prime. So no prime can be a perfect number and since 13 is prime, it cannot be a perfect number.