Two supplementary angles add up to 180 degrees. If one of the angles is x degrees, then the other angle will be 3x - 60. So we have: x + 3x - 60 = 180 4x - 60 + 60 = 180 + 60 4x = 240 4x/4 = 240/4 x = 60 3x - 60 = 3(60) - 60 = 120 Thus, the angles have measures of 60 and 120 degrees.
3
Say angle 1 is 40 which means that if angle 3 is congruent then angle 3 is also 40 by definition of vertical angles. That would make angle 2 equal to 140 by definition of a linear pair and so angle 4 is congruent by vertical angles.
3 angle
The angles are supplementary ===> A + B = 180 ===> A = 180 - B. Next statement: 3A = 2B - 5 (We don't know or care yet which one is larger, nor do we need to. That will come out on its own.) Substitute the first into the second: 3(180-B) = 2B-5 ===> (540-3B) = (2B-5 ) ===> 540 = 5B-5 ===> 545 = 5B109 = B ===> 71 = A
Without a visual or more information, I'm guessing that the picture is of angles 1 and 2 that are consecutive (share an angle side) and a separate picture of consecutive angles 3 and 4. With that said: 1) angle 2 congruent to angle 3................1) given 2) angle 1 is supplementary to angle 2....2) If angles are next to each other --> supps angle 3 is supplementary to angle 4 3) angle 1 congruent angle 4..............3) If supps to congruents angles ---> congruent
120 (2/3 of 180)
The 3 interior angles of any triangle add up to 180 degrees.
Opposite angle are equal and adjacent angles are supplementary. Thus the other 3 angles are 91o, 89o & 91o.
No, because the sum of the 3 angles of a triangle always equals 180 degrees. If two angles are supplementary by definition the two together already sum to 180 degrees, leaving no "space" for the third angle.
Supplementary angles can have any number of angles as long as the angles add up to 180 degrees.
No. Any angles which add up to 180 degrees are supplementary.
Being a quadrilateral, the sum of all four angles is 360o.Opposite angles of a parallelogram are equal.Adjacent angles of a parallelogram are supplementary, that is add to 180o.Given one angle of a parallelogram, the other 3 angles can be calculated:the opposite angle is the same;the other two angles are the same as each other and are 180o - the_given_angle
Up to 3 angles that add to 180 degrees.
Angle 'A' is 7 more than 3 times angle 'B': A = 3B + 7 The angles are supplementary: A + B = 180 or A = (180 - B) (180 - B) = 3B + 7 180 = 4B + 7 173 = 4B B = 43.25 degrees A = 136.75 degrees Their difference is 93 degrees.
call the small angle x, then given the ratios we have x+2x+3x=180 6x=180 so x=30 The angles are 30, 60, and 90.
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1